Answer:
C. It is not a good fit because there are no points on the line.
Step-by-step explanation:
In order for a line to be a good fit for a data set represented as a scatterplot, the line must follow the general trend of the data in the scatterplot. This line does not follow the general trend of the data on the scatterplot, thus option (C) is the best statement to describe the situation.
C. It is not a good fit because there are no points on the line.
First: Please use the symbol " ^ " to indicate exponentiation. Your f(x) should be x^2, not x2. "x^2" reads "the square of x."
Let y equal g(x) = f(x) + k: y = <span>g(x) = f(x) + k. See that "k" is a y value?
If k=1, we merely translate the graph of f(x)=x^2 UP one scale division to obtain the graph of g(x) = f(x) + 1.
So, how does the range of g(x) compare to the range of f(x)? </span>
60. You just multiply them :)
Answer:
Y=x+1 = 1 solutions
Y=2x - 5 = 2 soluions
Step-by-step explanation:
AC is the hypotenuse of triangle ABC.
Because the length is 6√2 and angle A is 45 degrees, we know the length of both sides is 6.
This means AB is 6, which it the hypotenuse of triangle BCD.
Using cos(angle) = adjacent leg / hypotenuse we can find x:
cos(60) = X / 6
x = 6 * cos(60)
x = 3
