Is 3.67676767 a irrational number
1 answer:
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Answer:
a) 0.0498
b) 0.1489
c) 0.1818
Step-by-step explanation:
Given:
Number of telephones = 6+6+6= 18
6 cellular, 6 cordless, and 6 corded.
a) Probability that all the cordless phones are among the first twelve to be serviced:
12 are selected from 18 telephones, possible number of ways of selection = ¹⁸C₁₂
Then 6 cordless telephones are serviced, the remaining telephones are: 12 - 6 = 6.
The possible ways of selecting thr remaining 6 telephones = ¹²C₆
Probability of servicing all cordless phones among the first twelve:
= (⁶C₆) (⁶C₁₂) / (¹⁸C₁₂)
b) Probability that after servicing twelve of these phones, phones of only two of the three types remain to be serviced:
Here,
One type must be serviced first
The 6 remaining to be serviced can be a combination of the remaining two types.
Since there a 3 ways to select one type to be serviced, the probability will be:
= 3 [(⁶C₁)(⁶C₅) + (⁶C₂)(⁶C₄) + (⁶C₃)(⁶C₃) + (⁶C₄)(⁶C₂) + (⁶C₅)(⁶C₁)] / ¹⁸C₁₂
c) probability that two phones of each type are among the first six:
(⁶C₂)³/¹⁸C₆
Answer:
The equation that best represents the line that is parallel to 3x - 4y = 7 and passes through the point (-4, -2) is y = 3/4x + 1.
Step-by-step explanation:
3x - 4y = 7 and (-4, -2)
First, solve for y in the equation:
3x - 4y = 7
-4y = -3x + 7
4y = 3x - 7
y = 3/4x - 7/4
m = 3/4 (This will be the slope of the parallel line.) and (-4, -2)
Use the point-slope equation to find the equation that will best represent a parallel line:
y − y1 = m(x − x1)
y - -2 = 3/4(x - -4)
y + 2 = 3/4x + 3 (the 4s cancel out)
(3/4 x 4/1 = 3)
y = 3/4x + 1
The graph that I attached is what these two equations would look like graphed. I am not sure what you mean by two options, I'm sorry!
