Question

What is the perimeter of rectangle WXYZ, with vertices W(-3,7), X(-5,4), Y(1,0), and Z(3,3) to the nearest unit. 20,237 results

Answer 1

Use the distance formula to find width and length D= sqrt[(x2−x1)^2+(y2−y1)^2], then use the perimeter formula, P=2width+2length

Answer 2

Answer:

The perimeter of rectangle WXYZ is $6\sqrt{13}\approx 21.633$

Step-by-step explanation:

A rectangle WXYZ, with vertices W(-3,7), X(-5,4), Y(1,0), and Z(3,3).

Distance formula: $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using distance formula to find length of each side of rectangle.

Length of Side WX

$WX=\sqrt{(-3+5)^2+(7-4)^2}=\sqrt{13}$

Length of Side XY

$WX=\sqrt{(1+5)^2+(0-4)^2}=2\sqrt{13}$

Length of Side YZ

$WX=\sqrt{(3-1)^2+(3-0)^2}=\sqrt{13}$

Length of Side WZ

$WX=\sqrt{(3+3)^2+(7-4)^2}=2\sqrt{13}$

Perimeter of rectangle = 2(L+B)

$B=WX=YZ=\sqrt{13}$

$L=XY=WZ=2\sqrt{13}$

$P=2(\sqrt{13}+2\sqrt{13})$

$P=6\sqrt{13}$

Hence, The perimeter of rectangle WXYZ is $6\sqrt{13}\approx 21.633$