The <em>correct answers</em> are:
5x²+70x+245 ≥ 1050; and
Yes.
Explanation:
Let x be the width of the tablet. Since the width of the TV is 7 inches more than the tablet, the width of the TV would be x+7.
The length of the TV is 5 times the width; this makes the length 5(x+7) = 5x+35.
The area of the TV would be given by
(x+7)(5x+35).
Since Andrew wants the area to be at least 1050, we set the expression greater than or equal to 1050:
(x+7)(5x+35) ≥ 1050
Multiplying this, we have:
x*5x+x*35+7*5x+7*35 ≥ 1050
5x²+35x+35x+245 ≥ 1050
Combining like terms,
5x²+70x+245 ≥ 1050
To see if 8 is a reasonable width for the tablet, we substitute 8 for x:
5(8²)+70(8)+245 ≥ 1050
5(64)+560+245 ≥ 1050
320+560+245 ≥ 1050
1125 ≥ 1050
Since this inequality is true, 8 is a reasonable width.
Answer:
Step-by-step explanation:
we have a 51 in sandwich
let a piece be x
we have x= shorter piece
another piece is x+6
another piece (x+6)-9=x-3
x+x+6+x-3=51
3x=51-3
3x=48
x=48/3=16
x=16, longer piece is 16+6=22, shorter piece =10
2x -5x
3a + 10a
And -5
Combine and you get:
-3x + 13a - 5
Your answer is A.) for ur problem
