Answer:
The length of a rectangle is 3” more than twice the width. The area of the rectangle is 150 in^2. Find the dimensions of the rectangle.
The length of a rectangle is 3” more than twice the width. The area of the rectangle is 150 in^2. Find the dimensions of the rectangle.
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MATH QUADRATIC FORMULA
Kyle C. asked • 05/05/16
The length of a rectangle is 3” more than twice the width. The area of the rectangle is 150 in^2. Find the dimensions of the rectangle.
The length of a rectangle is 3” more than twice the width. The area of the rectangle is 150 in^2. Find the dimensions of the rectangle.
ANSWER
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We know that Area = Length x Width
in this case, L = 2W + 3 and A = 150in2
so, 150in2 = W x (2w + 3)
150in2 = 2W2 + 3W
rearranging, 2W2 + 3W - 150in2 = 0
we need to use the quadratic formula to solve this equation
that formula is [-b±(√b2 -4ac)]/2a
a = 2, b = 3, c = -150
inserting those values, we get [-3±(√32 -4•2•-150)]/2•2
which becomes (-3±√1209)/4
we get (-3 ± 34.771)/4
we can discard the negative value, because no length can be negative
so, W ≅ 7.942 inches
then L = 2W + 3 ≅ 18.886 inches
Proof: 7.942in x 18.886in ≅ 149.99
HOPE IT'S HELPFUL
THANK YOU
