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garik1379 [7]
3 years ago
11

In a young woman's study group, 7 percent of the students are from the town where the young woman's school is located, 80 percen

t are from in-state (but not from the school's town), and the rest are from outside the state. What percent of study group students is from outside the state?
Mathematics
1 answer:
Umnica [9.8K]3 years ago
5 0

Answer: the percent of study group students from outside the state is 13%

Step-by-step explanation:

The total number of students in the young woman's study group that are from the town where the young woman's school is located is 7%

The total number of students in the young woman's study group that are from in-state (but not from the school's town) is 80%.

Since the rest are from outside the state, the percent of study group students from outside the state would be

100 - (80 + 7) = 100 - 87 = 13%

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1. Michael and 6 friends went to the movies. There, they each bought movie tickets and a bag of popcorn to share among them all.
Aleonysh [2.5K]

Answer:

The variable is t

t represent the cost of movie tickets

Step-by-step explanation:

Given:

Total cost = 7t + 4.50

The variable is t

Michael + 6 friends = 7 people

4.50 represent the cost of popcorn

t represent the cost of movie tickets

For instance,

If the cost of a movie tickets is $2

Then,

t = 2

Total cost = 7t + 4.50

= 7(2) + 4.50

= 14 + 4.50

= 18.50

Total cost = $18.50

5 0
3 years ago
A) Use the definition of Laplace transform to find L{f }. (Do the integrals.) For what values of s is L{f } defined?f(t) = (2t+1
kiruha [24]

For the given function f(t) = (2t + 1) using definition of Laplace transform the required solution is L(f(t))s = [ ( 2/s²) + ( 1/s) ].

As given in the question,

Given function is equal to :

f(t) = 2t + 1

Simplify the given function using definition of Laplace transform we have,

L(f(t))s = \int\limits^\infty_0 {f(t)e^{-st} } \, dt

          =  \int\limits^\infty_0[2t +1] e^{-st} dt

          = 2\int\limits^\infty_0 te^{-st} + \int\limits^\infty_0e^{-st} dt

         = 2 L(t) + L(1)

L(1) = \int\limits^\infty_0e^{-st} dt

     = (-1/s) ( 0 -1 )

     = 1/s , ( s >  0)

2L ( t ) = 2\int\limits^\infty_0 te^{-st}

        =  2[t\int\limits^\infty_0 e^{-st} - \int\limits^\infty_0 ({(d/dt)(t) \int\limits^\infty_0e^{-st} \, dt )dt]

        =  2/ s²

Now ,

L(f(t))s = 2 L(t) + L(1)

          = 2/ s² + 1/s

Therefore, the solution of the given function using Laplace transform the required solution is L(f(t))s = [ ( 2/s²) + ( 1/s) ].

Learn more about Laplace transform here

brainly.com/question/14487937

#SPJ4

8 0
1 year ago
If measure 4 is 36 degrees what is the measure of angle 2
elena55 [62]
Acute angle between 0 and 90 degrees I think
7 0
3 years ago
The solution for the system equations 8x-6y=-32 and -8x+5y=36
Ghella [55]

Answer:

x=47, y=68

Step-by-step explanation:

Add the two equations. Then we get

-y=-68

y=68

Substituting the value of y in the first equation,

8x-6(68)=-32

8x-408=-32

8x=376

x=47

6 0
3 years ago
If 56% of people own a dog and 5 people are chosen at random, what is the probability that at least one person owns a dog?
wariber [46]

Answer:

2.8

Step-by-step explanation:

we do 56% times 5= 2.8

so 2.8 is your answer

(this answer was given by my friend who claims this is true.)

4 0
2 years ago
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