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Tems11 [23]
2 years ago
15

What is the area of the square? Help me pls

Mathematics
1 answer:
Allushta [10]2 years ago
8 0

Answer and Step-by-step explanation:

First, we need to find out the circumference of the circle.

We know that the circle has a radius of 1, and that we are finding the circumference. We'll use the circumference equation of a circle.

2\pir

<u>Plug in 1 for r.</u>

2\pi (1) = 2\pi = circumference of circle

<u>Now, multiply the answer (the circumference) by 4 to get the perimeter of the square.</u>

<u />2\pi x 4 = 8\pi = perimeter of square

<u>Now, divide the perimeter by 4 to get what the side of the square is.</u>

<u />8\pi ÷ 4 = 2\pi

<u>Now, multiply </u>2\pi<u> by </u>2\pi<u> (side times side) to get the area.</u>

2\pi x  2\pi = 4\pi

The answer is A. 4\pi

<em><u>#teamtrees #PAW (Plant And Water)</u></em>

<em><u>I hope this helps!</u></em>

<em><u>Brainliest is appreciated,</u></em>

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Complete question is:

A large pool of adults earning their first drivers license includes 50% low- risk drivers, 30% moderate-risk drivers, and 20% high-risk drivers. Because these drivers have no prior driving record, an insurance company considers each driver to be randomly selected from the pool. This month, the insurance company writes 4 new policies for adults earning their first drivers license. What is the probability that these 4 will contain at least two more high-risk drivers than low-risk drivers?

Answer:

probability that these 4 will contain at least two more high-risk drivers than low-risk drivers = 0.0488

Step-by-step explanation:

Let H represent High risk

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L represent Low risk.

The following combinations will satisfy the condition that there are at least two more high-risk drivers than low-risk drivers: HHHH, HHHL, HHHM, HHMM

The HHHH case has probability 0.2 ⁴ = 0.0016

The HHHL case has probability 4 × 0.2³ × 0.3 = 0.0096 (This is because L can be in four different places)

Similarly, the HHHM case has probability 4 × 0.2 ³ × 0.5 = 0.016

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Summing all these probabilities, we have;

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