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kykrilka [37]
2 years ago
12

Hey guys I need help in these. Thanks in advance^^

Mathematics
1 answer:
Alexus [3.1K]2 years ago
7 0

Answer:

Read explanation

Step-by-step explanation:

The two operations that you will get the same answer for no matter what order you do it is addition and multiplication.

Bonus: Technically, if you had something like 1-2-3 you could rewrite it as 1 + (-2) + (-3) and now it won't matter the order and for something like 1/2/3 you could rewrite as 1 * (1/2) * (1/3) and not it wont matter the order too!

This propetie is called the associative property of addition and multiplication.

In the second question since its addition the order you do it in does not matter.

Why: If you think of it logically adding in a diffrent order than the question does not matter since in the end your still adding the same ammount.

Remember: You can only swap the orders if everything is addition or multiplication and remember your order of operations when using this propety in the years to come.

Hoped this helped, Eddie K.W.

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Solution:

From the given table, it is clear that the function f(x) is defined as:

f(x)=\{(-14,11),(-7,-12),(-12,-5),(9,1),(10,-2),(-2,13)\}

We know that if (a,b) is in the function f(x), then (b,a) must be in the function f^{-1}(x). So, the inverse function is defined as:

f^{-1}(x)=\{(11,-14),(-12,-7),(-5,-12),(1,9),(-2,10),(13,-2)\}

And,

f^{-1}(f(a))=f^{1}(b)

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Using (i), we get

f^{-1}(f(3.14))=3.14

Now,

f(f(-7))=f(-12)

f(f(-7))=5

Therefore, the required values are f^{-1}(f(3.14))=3.14 and f(f(-7))=5.

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