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Mathematics

1 answer:

Morgarella [4.7K]3 years ago

5 0

You are converting the numbers to a word problem.

1. 5+x = the number five plus x

2. 5-x= the number 5 minus x

3. 5x= five times x

4. 5/x= five divided by x

5. three-fourths of x plus 2

6. two minus three-fourths of x

7. 3 times x plus 10

8. ten times x plus three

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1 5/7÷4/9 = what's the answer and how to write the problem out

balu736 [363]

The solution to given expression $1\frac{5}{7} \div \frac{4}{9}$ is $\frac{27}{7}$ or 3.8571

Solution:

Given expression is:

$1\frac{5}{7} \div \frac{4}{9}$

First let us convert the mixed fraction to improper fraction

Multiply the whole number by the denominator.

Add the answer from Step 1 to the numerator.

Write answer from Step 2 over the denominator.

Thus we get,

$1\frac{5}{7} = \frac{1 \times 7 + 5}{7} = \frac{12}{7}$

Now the given expression becomes,

$1\frac{5}{7} \div \frac{4}{9} = \frac{12}{7} \div \frac{4}{9}$

Convert the problem to multiplication by changing the division sign to multiplication and inverting the fraction to the right of the sign

$\frac{12}{7} \div \frac{4}{9} = \frac{12}{7} \times \frac{9}{4}$

Multiply the numerators, multiply the denominators, and leave the product in factored form

$\frac{12}{7} \times \frac{9}{4} = \frac{27}{7}$

In decimal form we get,

$\frac{27}{7} = 3.8571$

Thus the solution to given expression is $\frac{27}{7}$ or 3.8571

4 0

3 years ago

a 40 gram sample of a substance that's used for drug research has a k-value of 0.1446. find the substance's half life in days

Novay_Z [31]

The applicable decay formula is:N = No*e^(-kt)WhereN = Mass left after time tNo = Original massk = constantt = half lifeUsing the values given,N/No = e^(-0.1446t) = 1/2ln (1/2) = -0.1446 t *ln e^1-0.6931 = -0.1446 tt = 0.6331/0.1446 = 4.79 daysTherefore, half-life is 4.8 days.

3 0

3 years ago

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Just help, my brain shutdown and its currently 9:51, so help me asap. <3

Sergeu [11.5K]

Answer:

B hope this helps!

Step-by-step explanation:

Trust <3

4 0

2 years ago

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