Question

Simplify Help me please

Answer 1

Answer:

$\frac{-27b^{6}}{c^{18}}$

Step-by-step explanation:

first distribute the ^3, -3^3=-27, for the variables, (x^y)^3=x^(3y) so (b^2)^3=b^6 and (c^-6)^3=c^-18. now we have $-27b^{6}c^{-18}$. Next we have to get rid of the negative in c^-18. x^-y=1/x^y so c^-18=$\frac{1}{c^{18}}$, plug it in and you get $\frac{-27b^{6}}{c^{18}}$