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dimaraw [331]
2 years ago
8

Simplify Help me please

Mathematics
1 answer:
Reika [66]2 years ago
6 0

Answer:

\frac{-27b^{6}}{c^{18}}

Step-by-step explanation:

first distribute the ^3, -3^3=-27, for the variables, (x^y)^3=x^(3y) so (b^2)^3=b^6 and (c^-6)^3=c^-18. now we have -27b^{6}c^{-18}. Next we have to get rid of the negative in c^-18. x^-y=1/x^y so c^-18=\frac{1}{c^{18}}, plug it in and you get \frac{-27b^{6}}{c^{18}}

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