3 years ago

Simplify Help me please

Mathematics

1 answer:

Reika [66]3 years ago

6 0

Answer:

$\frac{-27b^{6}}{c^{18}}$

Step-by-step explanation:

first distribute the ^3, -3^3=-27, for the variables, (x^y)^3=x^(3y) so (b^2)^3=b^6 and (c^-6)^3=c^-18. now we have $-27b^{6}c^{-18}$ . Next we have to get rid of the negative in c^-18. x^-y=1/x^y so c^-18= $\frac{1}{c^{18}}$ , plug it in and you get $\frac{-27b^{6}}{c^{18}}$

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