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2 years ago

Given that E=MC find E when M=20 and C =2.5

Mathematics

2 answers:

tresset_1 [31]2 years ago

8 0

Answer:

50 or 125

Step-by-step explanation:

if u want E=MC then it would be 20 ×2.5=50

if u what to find E=MC² then it would be 20×2.5×2.5 =125

ACCORDING TO ME THIS SHOULD BE THE ANSWER, BUT NOT QUITE SURE ABOUT THIS.

Marina86 [1]2 years ago

8 0

Answer:

E = 50

Step-by-step explanation:

If M=20 and C=2.5, replace the letters in the equation with their numerical values so E=20*2.5

20*2.5 = 50

thus E=50

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Maksim231197 [3]

Answer:

A sample of 1077 is required.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is of:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

42% of freshmen do not visit their counselors regularly.

This means that $\pi = 0.42$

98% confidence level

So $\alpha = 0.02$ , z is the value of Z that has a pvalue of $1 - \frac{0.02}{2} = 0.99$ , so $Z = 2.327$ .

How large of a sample size is required?

A sample size of n is required, and n is found when M = 0.035. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.035 = 2.327\sqrt{\frac{0.42*0.58}{n}}$

$0.035\sqrt{n} = 2.327\sqrt{0.42*0.58}$

$\sqrt{n} = \frac{2.327\sqrt{0.42*0.58}}{0.035}$

$(\sqrt{n})^2 = (\frac{2.327\sqrt{0.42*0.58}}{0.035})^2$

$n = 1076.8$

Rounding up:

A sample of 1077 is required.

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3 years ago

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kakasveta [241]

Answer:

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Read 2 more answers

Given that E=MC find E when M=20 and C =2.5​

Given that E=MC find E when M=20 and C =2.5