Answer:
A) 
B) 
C) for n = 2
= 1
for n = 3
= 3
for n = 4
= 8
for n = 5
= 19
Step-by-step explanation:
A) A recurrence relation for the number of bit strings of length n that contain a pair of consecutive Os can be represented below
if a string (n ) ends with 00 for n-2 positions there are a pair of consecutive Os therefore there will be :
strings
therefore for n ≥ 2
The recurrence relation for the number of bit strings of length 'n' that contains consecutive Os
b ) The initial conditions
The initial conditions are : 
C) The number of bit strings of length seven containing two consecutive 0s
here we apply the re occurrence relation and the initial conditions
for n = 2
= 1
for n = 3
= 3
for n = 4
= 8
for n = 5
= 19
The area of a square is simply the side length squared and we are given that the area is 125 so:
s^2=125
s=√125
s=5√5
Now using the area equation again, and adding 1 inch to s we have:
A=(s+1)^2, and using s found above we have:
A=(5√5+1)^2
A=125+10√5+1
A=126+10√5 in^2
A≈148.36 in^2 (to nearest hundredth of a square inch)
<u>Answer:</u>
<u>Step-by-step </u><u>Explanation</u><u>:</u>
The sequence is following some rule. And the rule is: Multiplying the term with 4 to get the next term. Like:
Similarly, the next terms are:
The terms are <u>6</u><u>4</u><u>,</u><u> </u><u>2</u><u>5</u><u>6</u><u>,</u><u> </u><u>1</u><u>0</u><u>2</u><u>4</u> which matches with Option D. And that's the correct answer
Answer:
im pretty sure b
Step-by-step explanation:
because i took a test
A) 17/52
B) 15/26
C) 4/13
A) The probability of getting a club is 13/52; the probability of getting a 3 is 4/52; the probability of a club or 3 is
13/52+4/52 = 17/52
B) The probability of a red card is 26/52; the probability of a King is 4/52; the probability of a red card or King is
26/52+4/52=30/52 = 15/26
C) The probability of a 9 is 4/52; the probability of a face card is 12/52; the probability of a 9 or a face card is 4/52+12/52 = 16/52 = 4/13