Question

What is the following product? 3sqrt4 times sqrt3​

Answer 1

Answer:

$\sqrt[6]{432}$

Step-by-step explanation:

$\sqrt[3]{4}\cdot\sqrt{3}=4^{\frac{1}{3}}\cdot3^\frac{1}{2}=(2^2)^\frac{1}{3}\cdot3^\frac{1}{2}=(2^\frac{4}{3})^\frac{1}{2}\cdot3^\frac{1}{2}=(2^\frac{4}{3}\cdot3)^\frac{1}{2}=(2^4\cdot27)^\frac{1}{6}=432^\frac{1}{6}=\sqrt[6]{432}$