Ask question

Ask question

All categories

3 years ago

9

Write an equation that represents the line. Use exact numbers

1 answer:

dsp733 years ago

8 0

Answer:

y = 5/6x + 8/3

Step-by-step explanation:

y = mx + b (m is the slope, b is the y-intercept)

(-2, 1) (4, 6)

m = change in y / change in x

m = 5/6

y = 5/6x + b

Plugging in (4, 6):

6 = 5/6(4) + b

6 = 20/6 + b

36/6 = 20/6 + b

36/6 - 20/6 = b

b = 16/6

b = 8/3

y = 5/6x + 8/3

You might be interested in

How many different 4-question geometry quizzes can a teacher make if there are 7 different problems to test on?.

stich3 [128]

Answer:

35 quizzes

Step-by-step explanation:

We need to determine how many ways we can choose 4 questions out of 7 to make the quizzes.

We do this by using the formula $\displaystyle nCr=\frac{n!}{r!(n-r)!}$ which describes the number of ways we can choose $r$ objects given $n$ possible choices. So, if $n=7$ and $r=4$ , then:

$_4C_7=\frac{7!}{4!(7-4)!}\\\\_4C_7=\frac{7*6*5*4!}{4!*3!}\\\\_4C_7=\frac{210}{6}\\\\_4C_7=35$

Hence, the teacher can make 35 different geometry quizzes.

3 0

3 years ago

Which graphic organizer would help you visualize important events in the history of the U.S. space program? timeline point-by-po

Sergeu [11.5K]

Timeline would help your the most<span />

6 0

3 years ago

Read 2 more answers

X+y+z=12<br> 6x-2y+z=16<br> 3x+4y+2z=28<br> What does x, y, and z equal?

lianna [129]

Answer:

x = 20/13 , y = 16/13 , z = 120/13

Step-by-step explanation:

Solve the following system:

{x + y + z = 12 | (equation 1)

6 x - 2 y + z = 16 | (equation 2)

3 x + 4 y + 2 z = 28 | (equation 3)

Swap equation 1 with equation 2:

{6 x - 2 y + z = 16 | (equation 1)

x + y + z = 12 | (equation 2)

3 x + 4 y + 2 z = 28 | (equation 3)

Subtract 1/6 × (equation 1) from equation 2:

{6 x - 2 y + z = 16 | (equation 1)

0 x+(4 y)/3 + (5 z)/6 = 28/3 | (equation 2)

3 x + 4 y + 2 z = 28 | (equation 3)

Multiply equation 2 by 6:

{6 x - 2 y + z = 16 | (equation 1)

0 x+8 y + 5 z = 56 | (equation 2)

3 x + 4 y + 2 z = 28 | (equation 3)

Subtract 1/2 × (equation 1) from equation 3:

{6 x - 2 y + z = 16 | (equation 1)

0 x+8 y + 5 z = 56 | (equation 2)

0 x+5 y + (3 z)/2 = 20 | (equation 3)

Multiply equation 3 by 2:

{6 x - 2 y + z = 16 | (equation 1)

0 x+8 y + 5 z = 56 | (equation 2)

0 x+10 y + 3 z = 40 | (equation 3)

Swap equation 2 with equation 3:

{6 x - 2 y + z = 16 | (equation 1)

0 x+10 y + 3 z = 40 | (equation 2)

0 x+8 y + 5 z = 56 | (equation 3)

Subtract 4/5 × (equation 2) from equation 3:

{6 x - 2 y + z = 16 | (equation 1)

0 x+10 y + 3 z = 40 | (equation 2)

0 x+0 y+(13 z)/5 = 24 | (equation 3)

Multiply equation 3 by 5:

{6 x - 2 y + z = 16 | (equation 1)

0 x+10 y + 3 z = 40 | (equation 2)

0 x+0 y+13 z = 120 | (equation 3)

Divide equation 3 by 13:

{6 x - 2 y + z = 16 | (equation 1)

0 x+10 y + 3 z = 40 | (equation 2)

0 x+0 y+z = 120/13 | (equation 3)

Subtract 3 × (equation 3) from equation 2:

{6 x - 2 y + z = 16 | (equation 1)

0 x+10 y+0 z = 160/13 | (equation 2)

0 x+0 y+z = 120/13 | (equation 3)

Divide equation 2 by 10:

{6 x - 2 y + z = 16 | (equation 1)

0 x+y+0 z = 16/13 | (equation 2)

0 x+0 y+z = 120/13 | (equation 3)

Add 2 × (equation 2) to equation 1:

{6 x + 0 y+z = 240/13 | (equation 1)

0 x+y+0 z = 16/13 | (equation 2)

0 x+0 y+z = 120/13 | (equation 3)

Subtract equation 3 from equation 1:

{6 x+0 y+0 z = 120/13 | (equation 1)

0 x+y+0 z = 16/13 | (equation 2)

0 x+0 y+z = 120/13 | (equation 3)

Divide equation 1 by 6:

{x+0 y+0 z = 20/13 | (equation 1)

0 x+y+0 z = 16/13 | (equation 2)

0 x+0 y+z = 120/13 | (equation 3)

Collect results:

Answer: {x = 20/13 , y = 16/13 , z = 120/13

8 0

3 years ago

Someone help please! D:

Dahasolnce [82]

Answer:

D) (10,22)

Step-by-step explanation:

based on given slope and point, the linear equation is <em>y = 9/5x + 2</em>

plugging in x-and-y values only results in a true statement for option D

example:

22 = 9/5(10) + 2

Does 22 = 18 + 2? Yes

6 0

3 years ago

Spaceship Earth, a spherical attraction at Walt Disney worlds epcot center, has a diameter of 50 meters. Find the surface area o

gladu [14]

Answer:

The surface area of the structure is $SA=2,500\pi\ m^{2}$

Step-by-step explanation:

we know that

The surface area of a sphere is equal to

$SA=4\pi r^{2}$

In this problem we have

$r=50/2=25\ m$ -----The radius is half the diameter

substitute

$SA=4\pi (25)^{2}$

$SA=2,500\pi\ m^{2}$

5 0

3 years ago