3 years ago

If x^3+ax^2+bx=6 is exactly divisible by (x-1), prove that a+b=5.

Mathematics

1 answer:

nata0808 [166]3 years ago

6 0

Step-by-step explanation:

x-1=0

x=1

subtitute value of x

p(x)=x^3+ax^2+bx

p(1)=(1)^3+a(1)^2+b(1)

p(1)=1+a+b

as p(x) =6. (given)

1+a+b=6

a+b=6-1

a+b=5

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Shalnov [3]

Hello!

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3 years ago

Read 2 more answers

Which of the following expressions is equivalent to (x + 5) ^2

Karo-lina-s [1.5K]

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the expression that is equivalent to

To multiply it we apply FOIL method
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3 years ago

Help plz<br> Solve for f.<br> 4(f + 2) = 16

Gnesinka [82]

Answer:

Step-by-step explanation:

4(f+2)=16

4f+8=16

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