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3 years ago

Fill in the blanks. Algebra 1 course.

Mathematics

1 answer:

Goshia [24]3 years ago

7 0

Answer:

1st blank: -9

2nd blank: 72

3rd blank: 22

Step-by-step explanation:

assume p=-10

5(-10)-8(-10+1)>16

-50-8(-9)>16

-50+72>16

22>16

This statement is true, so p=-10 is an answer

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You have a 1200-foot roll of fencing and a large field. you want to make two paddocks by splitting a rectangular enclosure in ha

romanna [79]

Let width = w
Let length = l
Let area = A
3w+2l=1200
2l=1200-3w
l=1200-3/2
A=w*l
A=w*(1200-3w)/2
A=600w-(3/2)*w^2
If I set A=0 to find the roots, the maximum will be at wmax=-b/2a which is exactly 1/2 way between the roots-(3/2)*w^2+600w=0
-b=-600
2a=-3
-b/2a=-600/-3
-600/-3=200
w=200
And, since 3w+2l=1200
3*200+2l=1200
2l = 600
l = 300
The dimensions of the largest enclosure willbe when width = 200 ft and length = 300 ft
check answer:
3w+2l=1200
3*200+2*300=1200
600+600=1200
1200=1200
and A=w*l
A=200*300
A=60000 ft2
To see if this is max area change w and l slightly but still make 3w+2l=1200 true, like
w=200.1
l=299.85
A=299.85*200.1
A=59999.985

8 0

3 years ago

Expanding triple brackets i will give brainliest!

swat32

Answer:

$x^{3} -13x^{} -12$

Step-by-step explanation:

(x+1) (x−4) (x+3)

= ((x+1)(x−4)) (x+3)

= ((x+1)(x−4)) (x)+((x+1)(x−4)) (3)

= $x^{3} -3x^{2} -4x^{} +3x^{2} -9x^{} -12$

= $x^{3} -13x^{} -12$

7 0

2 years ago

Help please <br> 5x-2y=-10

Lena [83]

Answer:

$5x - 2y = - 10 \\ 5x = - 10 + 2y \\ x = \frac{ - 10 + 2y}{5} \\ \\$

when y=0,-5,5,-10,10

then x=-2,-4,0,-6,2

6 0

2 years ago

What is the distance rounded to the nearest tenth between the points (2 -2) and (6 3)

kotegsom [21]

Answer:

The distance between the points is approximately 6.4

Step-by-step explanation:

The given coordinates of the points are;

(2, -2), and (6, 3)

The distance between two points, 'A', and 'B', on the coordinate plane given their coordinates, (x₁, y₁), and (x₂, y₂) can be found using following formula;

$l = \sqrt{\left (y_{2}-y_{1} \right )^{2}+\left (x_{2}-x_{1} \right )^{2}}$