Ask question

Ask question

All categories

3 years ago

5

Write as a numeral in simplest form:(6x1000)+(4x100)+(6x1)

1 answer:

Anni [7]3 years ago

4 0

Answer:
6401
step-by-step explanation:
6 x 1000
6000
4 x 100
400
6 x 1
6
6401

You might be interested in

How do I find QS here?

docker41 [41]

Answer: 12.

To solve this problem, let's first solve for x. Thi is easiest done by figuring what QR is in terms of x using two equations, both from different lines.

In the first line:
QR = 15 - 4x.

In the third line:
QR = 13x - 1 - x = 12x - 1.

Now, we have to set these equations equal to each other.
15 - 4x = 12x - 1
15 = 16x - 1
16x = 16
x = 1

Next, we take line three, 13x - 1, and substitute x as 1. The answer is 12.

3 0

3 years ago

FREEEEEEEEEEEEEEEEEE POINTS GET RICHHHHHHHHHHHHHHHHHH

guajiro [1.7K]

Answer:

Richhhh!!! Thanks for the points!!

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

HELP HELP HELP<br> HELP HELP <br> HELP <br> (STEP BY STEP)

Marizza181 [45]

With some simple rearrangement, we can rewrite the numerator as

$2x^3 - 3x^2 - x + 4 = 2(x^3 - x) - 3x^2 + x + 4 \\\\ ~~~~~~~~ = 2x(x^2-1) - 3(x^2 - 1) + x + 1 \\\\ ~~~~~~~~ = (2x-3)(x^2-1) + x+1$

Then factorizing the difference of squares, $x^2-1=(x-1)(x+1)$ , we end up with

$\dfrac{2x^3 - 3x^2 - x + 4}{x^2 - 1} = \dfrac{(2x-3)(x-1)(x+1) + x+1}{(x-1)(x+1)} \\\\ ~~~~~~~~ = \boxed{2x-3 + \dfrac1{x-1}}$

3 0

2 years ago

I need help plzzzzz this is really confusing

Anuta_ua [19.1K]

Answer:

B. <u>x</u><u><</u><u> </u>-3

hope it helps.

<h3>stay safe healthy and happy.</h3>

5 0

3 years ago

Read 2 more answers

You have 100 feet of fencing and decide to make a rectangular garden. What is the largest area enclosed

k0ka [10]

Answer:

625 ft^2

Step-by-step explanation:

Given

$P = 100$ --- perimeter

Required

The largest area

The perimeter is calculated as:

$P = 2 * ( L + W)$

So, we have:

$2 * ( L + W) = 100$

Divide both sides by 2

$L + W = 50$

Make L the subject

$L = 50 - W$

The area is calculated as:

$A= L * W$

Substitute $L = 50 - W$

$A= (50 - W) * W$

Open bracket

$A = 50W - W^2$

Differentiate with respect to W

$A' = 50 -2W$

Set to 0; to get the maximum value of W

$50 - 2W = 0$

Collect like terms

$-2W = -50$

Divide by -2

$W = 25$

So, the maximum area is:

$A = 50W - W^2$

$A = 50 * 25 - 25^2$

$A = 1250 - 625$

$A = 625$

3 0

2 years ago