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2 years ago

Sin2alpha+cos2alpha-cos6alpha/sin4alpha+2sin²alpha-1 if alpha is -135°

Mathematics

1 answer:

balandron [24]2 years ago

5 0

Answer:

$= \frac{\sin(2 \alpha ) + \cos(2 \alpha ) - \cos(6 \alpha ) }{ \sin(4 \alpha ) + 2 { \sin }^{2} \alpha - 1} \\ = \frac{ \sin( - 270) + \cos( - 270) - \cos( - 810) }{ \sin( - 540) + 2 { \sin }^{2}( - 135) - 1 } \\ = \frac{1}{ - 2} \\ = - 0.5$

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Sin2alpha+cos2alpha-cos6alpha/sin4alpha+2sin²alpha-1 if alpha is -135°​

Sin2alpha+cos2alpha-cos6alpha/sin4alpha+2sin²alpha-1 if alpha is -135°