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pickupchik [31]
3 years ago
12

Sin2alpha+cos2alpha-cos6alpha/sin4alpha+2sin²alpha-1 if alpha is -135°​

Mathematics
1 answer:
balandron [24]3 years ago
5 0

Answer:

=  \frac{\sin(2 \alpha )  +  \cos(2 \alpha )  -  \cos(6 \alpha ) }{ \sin(4 \alpha )  + 2 { \sin }^{2}  \alpha  - 1}  \\  =  \frac{ \sin( - 270) +  \cos( - 270)  -  \cos( - 810)  }{ \sin( - 540)  + 2 { \sin }^{2}( - 135) - 1 }  \\  =  \frac{1}{ - 2}  \\  =  - 0.5

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