<span>1/2x+3y/4=5 => (1/2)x + (3/4)y = 5
1/5x+3y/2=2 => (1/5)x + (3/2)y = 2
Eliminate the fractional coefficients: Mult. the first equation by 4 and mult. the second equation by 10:
2x + 15y = 20
</span><span>Multiply the 1st equation by -1:
-</span>2x - 3y = -20
2x + 15y = 20
-------------------
12y = 0, so y = 0. Then the first equation becomes 2x + 3(0) = 20, or
x=10.
Solution is (10,0).
It only the last one.
Hope this helps :)
Answer:
17
Step-by-step explanation:
Number of students in soccer club, n(S) = 50
Number of students in Art club, n(A) = 53
Number of students in Gaming club, n(G)
n(
) = 100
n(
) = 9
n(
) = 20
n(
) = 35
n(
) = 29
Formula:
n ( A ∪ B ∪ C ) = n(A) + n(B) + n(C) – n ( A ∩ B ) – n(B ∩ C) – n (A ∩ C) + n( A ∩ B ∩ C )
Putting the values:
100 = 50 + 53 + n(G) - 20 - 35 - 29 + 9
100 = 112 + n(G) - 84
n(G) = 72
Number of students in gaming club only = n(G) - n() - n() + n()
= 72 - 35 - 29 + 9
= <em>17</em>
1. <span>-0.9x+2.8=4.1
First subtract 2.8 from both sides.
-0.9x = 1.3
Now divide both sides by -0.9.
x = -1.4444..
This can be rounded to -1.44
</span><span>c) -1.44
2. Jordan has 650 pennies. He'll give 85 to his brother and split the rest with his sister.
</span>d) 85+2x=650
280 mg = 70 Ml
280/70 = 4
50 mL x 4 = 200 mg
200 mg
