There is two hundred and four (204) on a standard chessboard.
The number of red beads are increasing by 2 for each new pattern
The next number of reds will be 12. ( in patern 5)
number of blue beads in pattern 5 will be 15 ( increasing by 3 )
nth term for red = 4 + 2 (n-1) ( its an arithmetic sequence)
nth term for blue = 3 + 3(n - 1) - as above ,arithmetic.
Total beads in pattern 45 is
No. red beads in pattern 26 = 4 + 2(26-1) = 4 + 50 = 54
No blue beads in pattern 60 = 3 + 3(59) = 180
Total number of beads in pattern 45 is:-
4 + 2(44) + 3 + 3(44) = 227
Answer:
110 test
Step-by-step explanation:
Let
x ----> the number of packet of 10 test
y ----> the total cost
we know that
The number of packet of 10 test purchase multiplied by $11 plus the enrollment fee of $30 must be equal to $151
so
The linear equation that represent this scenario is
we have
substitute
Solve for x
subtract 30 both sides
Divide by 11 both sides
The number of packets purchase was 11
To find out the number of test, multiply the number of packets by 10
Answer:
15 : 29
Step-by-step explanation:
(3 3/4) / (7 1/4) = ((3·4+3)/4) / ((7·4+1)/4)
= (15/4) / (29/4) = 15/29
The ratio of the two numbers is 15 : 29.
Answer:
Open dot on 4 with arrow going to the right.
Step-by-step explanation:
4 is open because it is not part of the set.
