Question

Please answer this!!!​

Answer 1

Answer:

$BC=40$

Step-by-step explanation:

Since AC is a tangent and PB is the raduis

$\angle PBC= 9$

By pythagoras

$PC^{2} =PB^{2} +BC^{2}$

$41^{2} =9^{2} +BC^{2}$

$1681-81=BC^{2}$

$1600=BC^{2}$

$BC=\sqrt{1600}$

$BC=40$

OAmalOHopeO

Answer 2

Answer:

40

Step-by-step explanation:

A tangent to a circle is perpendicular to the radius intersection by definition. That makes BPC a right triangle at B.  BP and PD are both equal (9) because every radius of a circle is equal.  So

PC**2 = BP**2 + BC**2   or

41**2 = 9**2 + BC**2

1681 = 81 + BC**2

1681 - 81 = BC**2

1600 = BC**2

40 = BC