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Sindrei [870]
3 years ago
15

Please answer this!!!​

Mathematics
2 answers:
Mnenie [13.5K]3 years ago
7 0

Answer:

BC=40

Step-by-step explanation:

Since AC is a tangent and PB is the raduis

\angle PBC= 9

By pythagoras

PC^{2} =PB^{2} +BC^{2}

41^{2} =9^{2} +BC^{2}

1681-81=BC^{2}

1600=BC^{2}

BC=\sqrt{1600}

BC=40

<u>OAmalOHopeO</u>

Lana71 [14]3 years ago
4 0

Answer:

40

Step-by-step explanation:

A tangent to a circle is perpendicular to the radius intersection by definition. That makes BPC a right triangle at B.  BP and PD are both equal (9) because every radius of a circle is equal.  So

PC**2 = BP**2 + BC**2   or

41**2 = 9**2 + BC**2

1681 = 81 + BC**2

1681 - 81 = BC**2

1600 = BC**2

40 = BC

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