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3 years ago

Please answer this!!!

Mathematics

2 answers:

Mnenie [13.5K]3 years ago

7 0

Answer:

$BC=40$

Step-by-step explanation:

Since AC is a tangent and PB is the raduis

$\angle PBC= 9$

By pythagoras

$PC^{2} =PB^{2} +BC^{2}$

$41^{2} =9^{2} +BC^{2}$

$1681-81=BC^{2}$

$1600=BC^{2}$

$BC=\sqrt{1600}$

$BC=40$

<u>OAmalOHopeO</u>

Lana71 [14]3 years ago

4 0

Answer:

Step-by-step explanation:

A tangent to a circle is perpendicular to the radius intersection by definition. That makes BPC a right triangle at B. BP and PD are both equal (9) because every radius of a circle is equal. So

PC**2 = BP**2 + BC**2 or

41**2 = 9**2 + BC**2

1681 = 81 + BC**2

1681 - 81 = BC**2

1600 = BC**2

40 = BC

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