Question

What is the focus of the parabola with equation y = x2?

Answer 1

Answer:

$focus=(0,\frac{1}{4})$

Step-by-step explanation:

We are given equation of parabola as

$y=x^2$

we can also write as

$y=1(x-0)^2+0$

now, we can compare

$y=a(x-h)^2+k$

and find a , h , and k

a=1

h=0

k=0

now, we can use focus formula

$focus=(h,k+\frac{1}{4a})$

now, we can plug values

$focus=(0,0+\frac{1}{4\times 1})$

$focus=(0,\frac{1}{4})$