<span>Given a circle with radius r = 8 and a sector with subtended angle measuring 45°, find the area of the sector and the arc length.
They've given me the radius and the central angle, so I can just plug into the formulas. For convenience, I'll first convert "45°" to the corresponding radian value of π/4:
A = ((pi/4)/2)(8^2) = (pi/8)(8^2) = 8pi, s = (pi/4)(8) = 2pi
area A = 8π, arc-length s = 2π
Given a sector with radius r = 3 and a corresponding arc length of 5π, find the area of the sector.
For this exercise, they've given me the radius and arc length. From this, I can work backwards to find the subtended angle.
Then I can plug-n-chug to find the sector area.
5pi = (theta)(3), (theta) = (5/3)pi
So the central angle is (5/3)π.
Then the area of the sector is:
A = ((5/3)pi / 2)*(3^2) = ((5/6)pi)*(9) = (15/2)pi
A = (15 pi) / 2
</span><span>90/360 = 0.25 pi sq ft</span>
Answer:
Step-by-step explanation:
11/12 ÷ 1/3 = 2 3/4, or 11/2 as a improper fraction
hope this helps
Answer:
quadrant I
Step-by-step explanation:
from left to right its II, I
I can’t see the numbers. I want to help but can’t see the numbers.
2X^2+4X-8-X^2+6X-4
X^2+4X-8+6X-4
X^2+10X-12
