Answer : The amount of margarine needed is 1 kg.
Step-by-step explanation :
First we have to convert volume of syrup from mL to L.
Conversion used:
1 L = 1000 mL
or, 1 mL = 0.001 L
So, 225 mL = 0.225 L
Now we have to calculate the amount of margarine needed.
As, 0.225 L of syrup needed 150 g of margarine
So, 1.8 L of syrup needed
of margarine
Amount of margarine needed = 1000 g = 1 kg (1 kg = 1000 g)
Therefore, the amount of margarine needed is 1 kg.
Answer:
A
Step-by-step explanation:
So we have the two functions:

And we want to find:

This is the same as:

So, to find the answer, find g(1) first:

Now, substitute this value for g(1):

And plug this into f(x):

Therefore:

Our answer is A
Answer:
22.6
Step-by-step explanation:
15-1 8-15
14^2 7^2
196+49
245
15.6
Answer:
Both ends go up.
Step-by-step explanation: