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3 years ago

Write the conjugate of the following complex number: -3 + 2i

Mathematics

1 answer:

katen-ka-za [31]3 years ago

4 0

Answer:

-3 - 2i

Step-by-step explanation:

conjugate of a+bi is a-bi, so conjugate of -3 + 2i = -3 - 2i

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PLEASE ANSWER the most understandable will get brainliest

katrin2010 [14]

Answer:

I think it should be the 1st one

Step-by-step explanation:

sorry if it is wrong hope it helps

4 0

3 years ago

Answer #1 please ASAP

Ad libitum [116K]

Answer:

4.5

Step-by-step explanation:

To find the median, put the data in order from smallest to largest

1,2,2,3,4,4,5,5,8,10,10,11

The count up the number of data points

Divide by 2

12/2

Split the data into 2 groups, 6 in each, starting at the beginning

1,2,2,3,4,4, 5,5,8,10,10,11

Since there is an even number

Add the last number in first group and the first number in the last group and divide by 2

(4+5)/2 = 9/2 = 4.5

The median is 4.5

6 0

3 years ago

Read 2 more answers

If n = 8 and 16 • 2m = 4n – 8, then m = ?

max2010maxim [7]

Answer:

m = 0.75

Step-by-step explanation:

16 x 2m = 4x8 - 8

32m = 24

m = 24/32

5 0

3 years ago

A+B=44 A+B=44 A:B A:B is equivalent to 4:7. A= B=

ipn [44]

I think is going to be
A=1
B=43
I WISH IF YOU LOOKING FOR

6 0

4 years ago

An equilateral triangle has a side length of 6. What is the height of the triangle?

vlabodo [156]

Since the height of an equilateral triangle in terms of its side s is s√3/2, the height of the triangle is 6√3/2 = 3√3 and so the area is (1/2)(6)(3√3) = 9√3.

If we draw a horizontal line a height of h from the base of the triangle, the region is split into two regions: the lower region consisting of a trapezoid of height h and the upper region consisting of a triangle of height 3√3 - h. 

Since the upper triangle and the triangle itself are similar triangles, the base and height are proportional. If we let x denote the base of the length of the upper triangle, we have: 

(S. of small triangle)/(S. of big triangle) = (Ht. of small triangle)/(Ht. of big triangle) 
==> x/6 = (3√3 - h)/(3√3) 
==> x = (6√3 - 2h)/√3 

Thus, the area of the upper triangle is: 

A = (1/2)[(6√3 - 2h)/√3](3√3 - h) = [(6√3 - 2h)(3√3 - h)]/(2√3). 
(Made a dumb mistake about the height here for some reason) 

Since we require that the area of this triangle is to be half of the total area (9√3/2), we need to solve: 

[(6√3 - 2h)(3√3 - h)]/(2√3) = 9√3/2 
==> (6√3 - 2h)(3√3 - h) = 27 
==> 54 - 6h√3 - 6h√3 + 2h^2 = 27 
==> 2h^2 - 12h√3 + 27 = 0. 

Solving with the Quadratic Formula gives: 

h = (6√3 + 3√6)/2 ≈ 8.87 units and h = (6√3 - 3√6)/2 ≈ 1.52 units. 

Since h = (6√3 + 3√6)/2 would place the line outside of the triangle, we pick h = (6√3 - 3√6)/2. 

Therefore, the line should be ==> (6√3 - 3√6)/2 units from the base. 

I hope this helps! ^^ Brainliest Please?

5 0

3 years ago

Read 2 more answers