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3 years ago

13

URGANT!!!!! Rhoda pays for internet access each month. the graph shows the relationship between the total amount and she has pai

d and the amount of time, in months.

1 answer:

aleksandr82 [10.1K]3 years ago

5 0

Tbh idek but I need the Brainly points sorry

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Philip and Veronica are in band together. He asked her a statistical question. Which question

Karo-lina-s [1.5K]

The answer would be D. H<span>ow long are the songs you practice playing on your instrument?

Statistical questions are ones that will show variability. The first three questions will have a straight answer. The last one however will have data that varies, since most likely every song is not the same length.
</span>

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3 years ago

Fill in the answer to 5+5=4+_

Gnom [1K]

Answer:

6

Step-by-step explanation:

5+5=10, so 4+6=10

4 0

3 years ago

Read 2 more answers

K means vs k medoids are the same when data set is large

Hitman42 [59]

<span>K-means clustering is a data mining learning algorithm used to cluster observations into groups of related observation without any prior knowledge of those relationships.
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3 years ago

9.4 The heights of a random sample of 50 college stu- dents showed a mean of 174.5 centimeters and a stan- dard deviation of 6.9

gladu [14]

Answer: a) (176.76,172.24), b) 0.976.

Step-by-step explanation:

Since we have given that

Mean height = 174.5 cm

Standard deviation = 6.9 cm

n = 50

we need to find the 98% confidence interval.

So, z = 2.326

(a) Construct a 98% confidence interval for the mean height of all college students.

$x\pm z\times \dfrac{\sigma}{\sqrt{n}}\\\\=(174.5\pm 2.326\times \dfrac{6.9}{\sqrt{50}})\\\\=(174.5+2.26,174.5-2.26)\\\\=(176.76,172.24)$

(b) What can we assert with 98% confidence about the possible size of our error if we estimate the mean height of all college students to be 174.5 centime- ters?

Error would be

$\dfrac{\sigma}{\sqrt{n}}\\\\=\dfrac{6.9}{\sqrt{50}}\\\\=0.976$

Hence, a) (176.76,172.24), b) 0.976.

8 0

3 years ago

How do you find DE, Round to nearest 10th

Sergeu [11.5K]

Answer: $DE\approx6.0$

Step-by-step explanation:

Observe in the figure given in the exercise that four right triangles are formed.

In this case you can use the following Trigonometric Identity to solve this exercise:

$cos\alpha=\frac{adjacent}{hypotenuse}$

From the figure you can identify that:

$\alpha =53\°\\\\hypotenuse=10\\\\adjacent=BE=DE$

Then, you can substitute values:

$cos(53\°)=\frac{DE}{10}$

The next step is to solve for DE in order to find its value. This is:

$10*cos(53\°)=DE\\\\DE=6.01$

Finally, rounding the result to the nearest tenth, you get that this is:

$DE\approx6.0$

7 0

3 years ago