Solve for M plz..............................
1 answer:
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I assume you want to know a permutation about how many ways they can be in the final set-up.
Order matters, which is why this is a permutation.
Formula: P(n, r) =
where the permutation is
, with P for permutation.
Plug in:
4!/(4-2)!
4!/2!
(1 x 2 x 3 x 4)/1 x 2
(3x4)/1
= 12
12 ways.
Order matters, which is why this is a permutation.
Formula: P(n, r) =
where the permutation is
Plug in:
4!/(4-2)!
4!/2!
(1 x 2 x 3 x 4)/1 x 2
(3x4)/1
= 12
12 ways.
Answer:
Option C.
Step-by-step explanation:
For a given set of N elements:
{x₁, x₂, ..., xₙ}
The mean is given by:
And the variance is given by:
Then for our set:
{70, 80 ,75, 75, 80}
We have 5 elements, then N = 5
The first thing we need to find is the mean.
Then the variance will be:
The correct option is C, 14.
Answer:
Step-by-step explanation:
