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LiRa [457]
3 years ago
12

Please help 10 points !!

Mathematics
1 answer:
enyata [817]3 years ago
4 0

The will intersect at a point with a positive x coordinate.

We can tell this because they actually already have a shared space on the graph. If you plot the 3 points of g(x) given, you'll see that f(x) and g(x) both share the coordinate (1, 3). As a result, we know that they do intersect and it is where x (1) is a positive number.

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8c, please and thank you!
Ivan

Step-by-step explanation:

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3 years ago
The exam had 60 questions.Phelix got 85% correct. How many questions did he answer correctly?
hichkok12 [17]
Y is 85% of 60

Equation: Y = P% * X

Solving our equation for Y
Y = P% * X
Y = 85% * 60

Converting percent to decimal:
p = 85%/100 = 0.85

Y = 0.85 * 60 
Y = 51
6 0
3 years ago
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A wall in Marcus's bedroom is 825825 feet high and 16231623 feet long. If he paints 1212 of the wall blue, how many square feet
Darina [25.2K]
1212 of what? The height or length?
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3 years ago
There are 3 measures of music that are played 3 times in a song. If the first measure has 8 notes, the second measure has 16 not
Mandarinka [93]
Hi!

We know that there are three measures and each has a different amount of notes. To find the total we add them all up.
8+16+4=28.

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5 0
3 years ago
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The time, t, required to travel a fixed distance varies inversely as the
Lemur [1.5K]

You must travel at 42 mph for 4 hours

<em><u>Solution:</u></em>

Time varies inversely as rate of motion

Let "t" be the time required

Let "r" be the rate of motion

Then, we get

t \propto \frac{1}{r}\\\\t = k \times \frac{1}{r}\\\\t = \frac{k}{r} -------- eqn 1

Where, "k" is the constant of proportionality

<em><u>You travel 3 hours at a rate of 56 mph</u></em>

Substitute t = 3 and r = 56 in eqn 1

3 = \frac{k}{56}\\\\k = 3 \times 56\\\\k = 168

<em><u>Find the  rate you must travel for 4 hours</u></em>

r = ? and t = 4

Substitute t = 4 and k = 168 in eqn 1

4 = \frac{168}{r}\\\\r = \frac{168}{4}\\\\r = 42

Thus you must travel at 42 mph for 4 hours

4 0
4 years ago
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