Answer: 0.14
Step-by-step explanation:
Given: Mean : 
In minutes , Mean : 
The exponential distribution function with parameter 
is given by :-
The probability of waiting more than 30 seconds i.e. 0.5 minutes is given by the exponential function :-
![P(X\geq0.5)=1-P(X\leq0.5)\\\\=1-\int^{0.5}_{0}4e^{-4t}dt\\\\=1-[-e^{-4t}]^{0.5}_{0}\\\\=1-(1-e^{-2})=1-0.86=0.14](https://tex.z-dn.net/?f=P%28X%5Cgeq0.5%29%3D1-P%28X%5Cleq0.5%29%5C%5C%5C%5C%3D1-%5Cint%5E%7B0.5%7D_%7B0%7D4e%5E%7B-4t%7Ddt%5C%5C%5C%5C%3D1-%5B-e%5E%7B-4t%7D%5D%5E%7B0.5%7D_%7B0%7D%5C%5C%5C%5C%3D1-%281-e%5E%7B-2%7D%29%3D1-0.86%3D0.14)
Hence, the probability of waiting more than 30 seconds = 0.14
Answer:
x- axis, I'm pretty sure
Step-by-step explanation:
Answer: 547
Step-by-step explanation: The margin of error formulae is given below as
Margin of error = critical value ×(σ/√n)
Where σ = standard deviation and n is the sample size.
From our question, margin of error = 0.08
Variance is 1.691,
hence σ = √variance = √1.691
= 1.3.
We will be using a z test for our critical value this is because a soft drink manufacturer will always produce drinks more than 30 in numbers.
The critical value for a 85% confidence interval is 1.44.
Hence critical value is 1.44.
By substituting the parameters, we have that
0.08 = 1.44 × 1.3/ √n
0.08 = 1.873/ √n
By cross multiplying
0.08 × √n = 1.873
√n = 1.873/ 0.08
√n = 23.41
n = (23.41)²
n = 547.
Answer:
y<-6 and y>10
Step-by-step explanation:
Answer:
a) 151lb.
b) 6.25 lb
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a random variable X, with mean 
and standard deviation 
, a large sample size can be approximated to a normal distribution with mean and standard deviation 
.
In this problem, we have that:
So
a) The expected value of the sample mean of the weights is 151 lb.
(b) What is the standard deviation of the sampling distribution of the sample mean weight?
This is 
