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3 years ago

Please solve these please

Mathematics

1 answer:

Irina-Kira [14]3 years ago

8 0

Answer:

A no. ans is 17a/20

B no. ans is 10c-7d/35

C no. ans is +1/−1⋅2/2⋅−1⋅3/2⋅−1⋅4

<h2>I only know this much answer.</h2><h3>Sorry. but hope this is helpfull.</h3>

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A farmer owns pigs, chickens, and ducks. When all her animals are together, she has 30 feathered animals, and the animals all to

tatiyna

To solve this problem, let us first assign some variables. Let us say that:

x = pigs

y = chickens

z = ducks

From the problem statement, we can formulate the following equations:

1. y + z = 30 ---> only chicken and ducks have feathers

2. 4 x + 2 y + 2 z = 120 ---> pig has 4 feet, while chicken and duck has 2 each

3. 2 x + 2 y + 2 z = 90 ---> each animal has 2 eyes only

Rewriting equation 1 in terms of y:

y = 30 – z

Plugging this in equation 2:

4 x + 2 (30 – z) + 2 z = 120

4 x + 60 – 2z + 2z = 120

4 x = 120 – 60

4 x = 60

x = 15

From the given choices, only one choice has 15 pigs. Therefore the answers are:

She has 15 pigs, 12 chickens, and 18 ducks.

3 0

3 years ago

Ok, so I'm pretty sure this one is 11.5 I just wanted to make sure with u guys! :)

Furkat [3]

Answer:

C: 23 cm

Step-by-step explanation:

This is the answer because:

1) Area of trapezoid is: (base1 + base2)/2 x height

2) In this case, it is 14 + 8 which is 22. 22/2 is 11.

3) Now we have to do 253/11 which is 23 cm.

Hope this helps! :D

4 0

3 years ago

Read 2 more answers

A test has 20 true/false questions. What is the probability that a student passes the test if they guess the answers? Passing me

Minchanka [31]

Using the binomial distribution, it is found that:

The probability that the student will get 15 correct questions in this test by guessing is 0.0207 = 2.07%.

For each question, there are only two possible outcomes, either the guess is correct, or it is not. The guess on a question is independent of any other question, hence, the binomial distribution is used to solve this question.

Binomial probability distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

n is the number of trials.

p is the probability of a success on a single trial.

In this problem:

There are 20 questions, hence $n = 20$ .

Each question has 2 options, one of which is correct, hence $p = \frac{1}{2} = 0.5$

The probability is:

$P(X \geq 15) = P(X = 15) + P(X = 16) + P(X = 17) + P(X = 18) + P(X = 19) + P(X = 20)$

In which:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 15) = C_{20,15}.(0.5)^{15}.(0.5)^{5} = 0.0148$

$P(X = 16) = C_{20,16}.(0.5)^{16}.(0.5)^{4} = 0.0046$

$P(X = 17) = C_{20,17}.(0.5)^{17}.(0.5)^{3} = 0.0011$

$P(X = 18) = C_{20,18}.(0.5)^{18}.(0.5)^{2} = 0.0002$

$P(X = 16) = C_{20,19}.(0.5)^{19}.(0.5)^{1} = 0$

$P(X = 17) = C_{20,20}.(0.5)^{20}.(0.5)^{0} = 0$

Then:

$P(X \geq 15) = P(X = 15) + P(X = 16) + P(X = 17) + P(X = 18) + P(X = 19) + P(X = 20) = 0.0148 + 0.0046 + 0.0011 + 0.0002 + 0 + 0 = 0.0207$

The probability that the student will get 15 correct questions in this test by guessing is 0.0207 = 2.07%.

You can learn more about the binomial distribution at brainly.com/question/24863377

6 0

3 years ago

Suppose f varies directly as g, and f varies inversely as h. Find g when f = 12 and h = 10, if g = 198 when h = –11 and f = –6.

sattari [20]

Answer:

360

Step-by-step explanation:

f varies directly as g

f = kg where k is the constant of variation

f varies inversely as h

f = kg/h

We know g = 198 when h = –11 and f = –6. Substituting in

-6 = k*198/(-11)

-6 =k*(-18)

Dividing each side by -18

-6/-18 = k*-18/-18

1/3 =k

Our equation is

f = 1/3 g/h

Letting f = 12 and h = 10

12 = 1/3 g/10

Multiply each side by 10

12*10 =1/3 g/10*10

120 = 1/3 g

Multiply each side by 3

120*3 =1/3 g *3

360 =g

5 0

3 years ago

To increase an amount by 3% what single multiplier would you use?<br> thanks :)

KATRIN_1 [288]

X - an amount

$x+3\%x=x+0.03x=1.03x$

To increase an amount by 3% you can multiply the amount by 1.03.

4 0

3 years ago

Please solve these please​

Please solve these please