3 years ago

¿Alguien sabe como realizarlo?

Mathematics

1 answer:

sashaice [31]3 years ago

7 0

Hola! Intente resolverlo pero solo hice la primera por mi tiempo ahorita mismo y era:
f(0)=1
Toda la ecuación

You might be interested in

Can someone please help me with this ?!!

bija089 [108]

Answer:

I believe the answer is B

Step-by-step explanation:

8 0

3 years ago

Which of the following represents the ratio of the long leg to the short leg in the right triangle shown below

madreJ [45]

D) 2:1 because long leg will be bigger, and small leg will be smaller, e.g. Long Leg(2): Small Leg(1)

6 0

4 years ago

Read 2 more answers

Simplify this equation please <br> (16a^8/c^12)^1/4

Tcecarenko [31]

Answer:

$\large\boxed{\left(\dfrac{16a^8}{c^{12}}\right)^\frac{1}{4}=\dfrac{2a^2}{c^3}}$

Step-by-step explanation:

$\left(\dfrac{16a^8}{c^{12}}\right)^\frac{1}{4}\qquad\text{use}\ \left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}\ \text{and}\ (a^n)^m=a^{nm}\ \text{and}\ (ab)^n=a^nb^n\\\\=\dfrac{(2^4a^8)^\frac{1}{4}}{(c^{12})^\frac{1}{4}}=\dfrac{(2^4)^\frac{1}{4}(a^8)^\frac{1}{4}}{c^{12\cdot\frac{1}{4}}}=\dfrac{2^{4\cdot\frac{1}{4}}\cdot a^{8\cdot\frac{1}{4}}}{c^3}=\dfrac{2^1\cdot a^2}{c^3}=\dfrac{2a^2}{c^3}$

4 0

3 years ago

Read 2 more answers

PLEASE PLEASE HELP I DON’T UNDERSTAND

frozen [14]

Answer:

You could do the adition and subtraction first then multiplication and division

Hope this helps

7 0

3 years ago

It is backwards so you will have to flip I need help on number 7 thank you so much

Gwar [14]

I dont really know but do you have to pick one of the numbers from the score board or no i dont really know what grade your in so idk .-. sorry if i cant help

3 0

4 years ago

Read 2 more answers