Calculate the percentage of O in CH₃COOH

Chemistry

1 answer:

nydimaria [60]3 years ago

6 0

Answer:

53.28%

(you could also write 55.33%, but I rounded it so just go with the answer above ---> 53.28%)

Explanation:

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HELP ASAP PLEASE!!!

puteri [66]

1. Pure substances cannot be separated into any other kinds of matter, while a mixture is a combination of two or more pure substances.

2. A pure substance has constant physical and chemical properties, while mixtures have varying physical and chemical properties (i.e., boiling point and melting point).

3. A pure substance is pure, while a mixture is impure.

8 0

3 years ago

An aqueous potassium iodate ( KIO3 ) solution is made by dissolving 562 562 grams of KIO 3 KIO3 in sufficient water so that the

maxonik [38]

Answer:

Molarity of $KIO_{3}$ solution is 0.612 mol/L

Explanation:

Number of moles of a substance = (mass of substance)/(molar mass of the substance)

Molar mass of $KIO_{3}$ = 214 g/mol

So, 562 g of $KIO_{3}$ = $\frac{562}{214}$ moles of $KIO_{3}$ = 2.63 moles of $KIO_{3}$

Molarity of a solution = (number of moles of solute in solution)/(total volume of solution in liter)

Here solute is $KIO_{3}$ and solvent is water

Total volume of solution is 4.30 L

So, molarity of $KIO_{3}$ solution = $\frac{2.63}{4.30}mol/L$ = 0.612 mol/L

3 0

3 years ago

For which of the following elements (in their normal, stable, forms) would it be correct to describe the bonding as involving a

Dvinal [7]

Answer: The correct option is e.

Explanation: In the given question it is asked to tell the element which has 'Sea of electrons' while bonding.

This means that the element should have extra electrons so that it can bond easily or this also means which element can easily donate its electron to form a bond.

Electronic configuration of Hydrogen = $1s^1$

Hydrogen cannot loose electrons easily because the electron is present in 1s sub-shell which is the closest to the nucleus and hence will be tightly bonded to it.