Answer:
hello your question is incomplete attached below is the complete question
Pyridinium ion is more soluble in 0.1 M HCL (aqueous solution) and this is because the Pyridine ion reacts with NaOH and after the reaction it comes out neutral.
N-acetyltyrosine methyl ester is more soluble in 0.1 M HCL while
B-napthol is more soluble in 0.1 M NaOH because it forms phenoxide ion
Explanation:
Pyridine ion is more soluble in 0.1 M HCL (aqueous solution) and this is because the Pyridine ion reacts with NaOH and after the reaction it comes out neutral.
N-acetyltyrosine methyl ester is more soluble in 0.1 M HCL while
B-napthol is more soluble in 0.1 M NaOH because it forms phenoxide ion
attached below is the remaining part of the solution
Answer:
23430.4 J.
Explanation:
From the question given above, the following data were obtained:
Mass (M) = 70 g
Initial temperature (T₁) = 10 °C
Final temperature (T₂) = 90 °C
Specific heat capacity (C) = 4.184 J/gºC
Heat (Q) required =?
Next, we shall determine the change in the temperature of water. This can be obtained as follow:
Initial temperature (T₁) = 10 °C
Final temperature (T₂) = 90 °C
Change in temperature (ΔT) =?
ΔT = T₂ – T₁
ΔT = 90 – 10
ΔT = 80 °C
Finally, we shall determine the heat energy required to heat up the water. This can be obtained as follow:
Mass (M) = 70 g
Change in temperature (ΔT) = 80 °C
Specific heat capacity (C) = 4.184 J/gºC
Heat (Q) required =?
Q = MCΔT
Q = 70 × 4.184 × 80
Q = 23430.4 J
Therefore, 23430.4 J of heat energy is required to heat up the water.
Answer:
Last option is the correct choice.
Explanation:
Number of protons = 60-33 = 27
Superscript 60 Subscript 27 upper C o.
Best Regards!
The main purpose of scientific methods, is to show the variations of the topic you are doing in science and how you are proving it to be that way.
