Question

An aqueous potassium iodate ( KIO3 ) solution is made by dissolving 562 562 grams of KIO 3 KIO3 in sufficient water so that the final volume of the solution is 4.30 L. Calculate the molarity of the KIO 3 KIO3 solution.

Answer 1

Answer:

Molarity of $KIO_{3}$ solution is 0.612 mol/L

Explanation:

Number of moles of a substance = (mass of substance)/(molar mass of the substance)

Molar mass of $KIO_{3}$ = 214 g/mol

So, 562 g of $KIO_{3}$ = $\frac{562}{214}$ moles of $KIO_{3}$ = 2.63 moles of $KIO_{3}$

Molarity of a solution = (number of moles of solute in solution)/(total volume of solution in liter)

Here solute is $KIO_{3}$ and solvent is water

Total volume of solution is 4.30 L

So, molarity of $KIO_{3}$ solution = $\frac{2.63}{4.30}mol/L$ = 0.612 mol/L