Q(p) = k/p^3 . . . . . . . . we want to find k
q(10) = k/10^3 = 64
k = 64,000
Revenue = q(p)*p = 64000/p^2
Cost = 150 +2q = 150 +2*64000/p^3
Profit = Revenue -Cost = 64000/p^2(1 -2/p) -150
Differentiating to find the maximum profit, we have
.. dProfit/dp = -2(64000/p^3) +6(64000/p^4) = 0
.. -1 +3/p = 0
.. p = 3
A price of $3 per unit will yield a maximum profit.
Use the substitution method:
2x - 6y = -12
x - 2y = -8
Then x = 2y - 8
Substitute in the first equation:
2(2y - 8) - 6y = -12
4y - 16 - 6y = -12
-2y = 4
y = -2
Now substitute y in one of the two equations given you prefer:
For example x-2*(-2) = -8
x + 4 = -8
x = -12
The solutions are x = -12 and y = -2
Ddcvv was a great night for you guys I love ya too
Answer:
392 minutes
Step-by-step explanation:
She reads 6/7 of a page in 12/5 mins
She will read 1 page in (12/5)* (7/6) mins
She will read 140 pages in (12/5)*(7/6)*140 mins = 392 mins
Answer:
4/3
x
Step-by-step explanation:

x + 4
4x
4
4x - x
4
3x
4/3
x