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Hoochie [10]
3 years ago
6

Plz help brainliest to correct answer

Mathematics
2 answers:
OverLord2011 [107]3 years ago
8 0
Each mark on the line is one unit. 0 is the starting point. For a positive number, move one unit at a time for the number you have. For example, to graph 2, start at 0 and move to the right 2 units. Just make a dot there and write 2 above it. For negative numbers, you go to the left. So start at 0, and go one to the left and that’s -1. Go one more to the left and that’s -2.
Maru [420]3 years ago
3 0

Answer:

-2 would be right next to -3 because its negative and -1 would be right next to -2, 2 would be two points away from 0 bc its a whole number

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4 x y -7y +9 x y + 12y
yulyashka [42]

Answer:13xy+5y

Step-by-step explanation:

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4 years ago
Bags of maple granola cost $2 more than apple granola
Brilliant_brown [7]

Answer:

a + m = 2+ a

Step-by-step explanation:

We don't know the amount of apple granola and the amount of the maple granola. So we just set an equation.

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4 years ago
How many megabytes of data can a 4.7 gigabyte dvd store?
dedylja [7]
The answer is 4700 megabytes.

1 giga = 1000 mega

1 gigabyte = 1000 megabyte
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1 gb : 1000 mb = 4.7 gb : x
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3 years ago
Which is the same as moving the decimal point 3 places to the left in a decimal
Ludmilka [50]
Multiplying the number by 1,000
5 0
3 years ago
In physics, if a moving object has a starting position at so, an initial velocity of vo, and a constant acceleration a, the
emmasim [6.3K]

Answer:

a=\frac{2S -2v_ot-2s_o}{t^2}

Step-by-step explanation:

We have the equation of the position of the object

S = \frac{1}{2}at ^2 + v_ot+s_o

We need to solve the equation for the variable a

S = \frac{1}{2}at ^2 + v_ot+s_o

Subtract s_0 and v_0t on both sides of the equality

S -v_ot-s_o = \frac{1}{2}at ^2 + v_ot+s_o - v_ot- s_o

S -v_ot-s_o = \frac{1}{2}at ^2

multiply by 2 on both sides of equality

2S -2v_ot-2s_o = 2*\frac{1}{2}at ^2

2S -2v_ot-2s_o =at ^2

Divide between t ^ 2 on both sides of the equation

\frac{2S -2v_ot-2s_o}{t^2} =a\frac{t^2}{t^2}

Finally

a=\frac{2S -2v_ot-2s_o}{t^2}

5 0
4 years ago
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