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professor190 [17]
3 years ago
5

Help, i will give u brainly. ASPA​

Mathematics
2 answers:
TiliK225 [7]3 years ago
8 0

Answer:

6, 24, 30, 48, 66

1, 4, 5, 8, 11

Step-by-step explanation:

Just by the first column we know that the scale ratio is 6. To find the second one we will multiply (6 * 4 = 24). To find the third one we will divide (30 / 6 = 5). To find the fourth one we will mulyiply (8 * 6 = 48). To find the fifth one we will divide (66 / 6 = 11).

Best of Luck!

erastova [34]3 years ago
3 0

Answer:

I need more information

Step-by-step explanation:

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You were playing fetch with your dog an accidentally threw the toy and it
enyata [817]

Answer:

8.1

Step-by-step explanation:

I got this answer of the internet good luck lol

5 0
3 years ago
Solve the given system of equations using either Gaussian or Gauss-Jordan elimination. (If there is no solution, enter NO SOLUTI
cricket20 [7]

Answer:

The system has infinitely many solutions

\begin{array}{ccc}x_1&=&-x_3\\x_2&=&-x_3\\x_3&=&arbitrary\end{array}

Step-by-step explanation:

Gauss–Jordan elimination is a method of solving a linear system of equations. This is done by transforming the system's augmented matrix into reduced row-echelon form by means of row operations.

An Augmented matrix, each row represents one equation in the system and each column represents a variable or the constant terms.

There are three elementary matrix row operations:

  1. Switch any two rows
  2. Multiply a row by a nonzero constant
  3. Add one row to another

To solve the following system

\begin{array}{ccccc}x_1&-3x_2&-2x_3&=&0\\-x_1&2x_2&x_3&=&0\\2x_1&+3x_2&+5x_3&=&0\end{array}

Step 1: Transform the augmented matrix to the reduced row echelon form

\left[ \begin{array}{cccc} 1 & -3 & -2 & 0 \\\\ -1 & 2 & 1 & 0 \\\\ 2 & 3 & 5 & 0 \end{array} \right]

This matrix can be transformed by a sequence of elementary row operations

Row Operation 1: add 1 times the 1st row to the 2nd row

Row Operation 2: add -2 times the 1st row to the 3rd row

Row Operation 3: multiply the 2nd row by -1

Row Operation 4: add -9 times the 2nd row to the 3rd row

Row Operation 5: add 3 times the 2nd row to the 1st row

to the matrix

\left[ \begin{array}{cccc} 1 & 0 & 1 & 0 \\\\ 0 & 1 & 1 & 0 \\\\ 0 & 0 & 0 & 0 \end{array} \right]

The reduced row echelon form of the augmented matrix is

\left[ \begin{array}{cccc} 1 & 0 & 1 & 0 \\\\ 0 & 1 & 1 & 0 \\\\ 0 & 0 & 0 & 0 \end{array} \right]

which corresponds to the system

\begin{array}{ccccc}x_1&&-x_3&=&0\\&x_2&+x_3&=&0\\&&0&=&0\end{array}

The system has infinitely many solutions.

\begin{array}{ccc}x_1&=&-x_3\\x_2&=&-x_3\\x_3&=&arbitrary\end{array}

7 0
3 years ago
10 POINTS!!! FULL ANSWER WITH FULL STEP BY STEP SOLUTION PLEASE. DO BOTH PARTS OF 1 AND ALL OF 2.
diamong [38]
One A
y = e^x
dy/dx = e^x The f(x) = the differentiated function. Any value that e^x can have, the derivative has the same value. x is contained in all the reals.
One B
y = x*e^x
y' = e^x + xe^x Using the multiplication rule.
You want the slope and the value of the of y to be the same. The slope is y' of the tangent line
xe^x = e^x + xe^x
e^x = 0
This happens only when x is very "small" like x = - 4444444

y = e^x * ln(x) Using the multiplication rule again, we need the slope of the line with is y'
y1 = e^x
y1' = e^x
y2 = ln(x)
y2' = 1/x
y' = e^x*ln(x) + e^x/x So at x = 1 the slope of the line = 
y' = e^1*ln(1) + e^1/1
y' = e*0+e  = e
y = mx + b
y = ex + b
to find b we use y= e^x ln(x)

e^x ln(x) = e*x + b
e^1 ln(1) = e*1 + b
ln(1) = 0
0 = e + b
b = - e

line equation and answer.
y = e*x - e
8 0
3 years ago
Keith works 8 hours per day for 5 per week. melba works 2,250 minutes each week. who spends more time at work
Orlov [11]

Answer:

Keith does.

Step-by-step explanation:

2250/60=37.5

8*5=40

Keith spends 40 hrs at work Melba spends 37.5 hrs.

6 0
4 years ago
6x - 2(x + 2) &gt; 2 - 3(x+3)<br><br>Solve the inequality <br><br>plz help ​
Mumz [18]

Answer:

x > -3/7

Step-by-step explanation:

6x - 2(x + 2) > 2 - 3(x + 3)

Distribute the two and three inside the parenthesis.

6x - 2x - 4 > 2 - 3x - 9

Combine like terms.

4x - 4 > -3x - 7

Add 4 to both sides.

4x > -3x - 3

Add 3x to both sides.

7x > -3

Divide both sides by 7.

x > -3/7

7 0
3 years ago
Read 3 more answers
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