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Ronch [10]
2 years ago
11

If y varies inversely with the square of x, and y = 26 when x = 4, find y when x = 2.

Mathematics
1 answer:
eduard2 years ago
3 0

Answer:

D. 104

Step-by-step explanation:

y \:  \alpha  \:  \frac{1}{ {x}^{2} }  \\  \\ y =  \frac{k}{ {x}^{2} }

when y is 26, x is 4:

26 =  \frac{k}{ {(4)}^{2} }  \\ k = 416

when x is 2:

y =  \frac{416}{ {x}^{2} }  \\ \\ y =  \frac{416}{ {(2)}^{2} }  \\ y = 104

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