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Ronch [10]
2 years ago
11

If y varies inversely with the square of x, and y = 26 when x = 4, find y when x = 2.

Mathematics
1 answer:
eduard2 years ago
3 0

Answer:

D. 104

Step-by-step explanation:

y \:  \alpha  \:  \frac{1}{ {x}^{2} }  \\  \\ y =  \frac{k}{ {x}^{2} }

when y is 26, x is 4:

26 =  \frac{k}{ {(4)}^{2} }  \\ k = 416

when x is 2:

y =  \frac{416}{ {x}^{2} }  \\ \\ y =  \frac{416}{ {(2)}^{2} }  \\ y = 104

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I really need help!!! It would mean a lot if someone could help me.
Rudiy27

The y answers would be 11, 8, 5, 2, -1.

To find these parts of the table, we simply put the x value in for x and solve for y. The first two are done for you below.

WHEN x = -2

y = -3x + 5

y = -3(-2) + 5

y = 6 + 5

y = 11

WHEN x = -1

y = -3x + 5

y = -3(-1) + 5

y = 3 + 5

y = 8

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