Question

If y varies inversely with the square of x, and y = 26 when x = 4, find y when x = 2.

Answer 1

Answer:

D. 104

Step-by-step explanation:

$y \: \alpha \: \frac{1}{ {x}^{2} } \\ \\ y = \frac{k}{ {x}^{2} }$

when y is 26, x is 4:

$26 = \frac{k}{ {(4)}^{2} } \\ k = 416$

when x is 2:

$y = \frac{416}{ {x}^{2} } \\ \\ y = \frac{416}{ {(2)}^{2} } \\ y = 104$