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3 years ago

The graph below does not represent a function. Explain why.

Mathematics

1 answer:

Simora [160]3 years ago

6 0

Notice how points T and Z are vertically aligned, or vertically lined up. This is where the graph fails the vertical line test.

The input x = 2 leads to the outputs y = 3 and y = 5 (which are the y coordinates of points Z and T in that order).

A function is only possible when any given input leads to <u>exactly one</u> output only. It would be like saying "the conversion function from Celsius to Fahrenheit has 0 degrees C convert to both 32 degrees F and 50 degrees F at the same time". But such a statement makes no sense and it's not useful. So this is one example of why having one output makes sense for a function.

In short, we need one output for any given input. But the input x = 2 leads to more than one output. That's why we don't have a function.

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2. The average score of all golfers for a particular course has a mean of 75 and a standard deviation of 4.5. Suppose we going t

stiv31 [10]

Answer:

$P(\bar X>76)$

And we can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 76 we got:

$z =\frac{76-75}{\frac{4.5}{\sqrt{81}}}= 2$

And if we use the complement rule and the normal standard distribution or excel we got:

$P(Z>2) = 1-P(Z$

And we can find this using the ti 84 with the following code:

1-normalcdf(-1000, 76, 75, 0.5 )

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

Let X the random variable who represent the score of golfers. We select a sampel size of 81.

From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And we want to find this probability:

$P(\bar X>76)$

And we can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 76 we got:

$z =\frac{76-75}{\frac{4.5}{\sqrt{81}}}= 2$

And if we use the complement rule and the normal standard distribution or excel we got:

$P(Z>2) = 1-P(Z$

And we can find this using the ti 84 with the following code:

1-normalcdf(-1000, 76, 75, 0.5 )

6 0

3 years ago

The number 312 lies between what two perfect squares?

Len [333]

Answer:
B) 216 and 330
or
C) 216 and 343

Well, for starters, I will pick B) 216 and 330 as my answer because its closer than C) 216 and 343, even though both can be the answer.

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3 years ago

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Select whether the number is rational, irrational, or imaginary. 1/4

rjkz [21]

Because 1/4 is a fractional number, it is also a ratio which means it is Rational. :)

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3 years ago

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Point K is graphed on a number line at 3. Point L is 11 units away from point K on the number line.

LUCKY_DIMON [66]

The points would be either: -8 or 14