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2 years ago

The graph below does not represent a function. Explain why.

Mathematics

1 answer:

Simora [160]2 years ago

6 0

Notice how points T and Z are vertically aligned, or vertically lined up. This is where the graph fails the vertical line test.

The input x = 2 leads to the outputs y = 3 and y = 5 (which are the y coordinates of points Z and T in that order).

A function is only possible when any given input leads to exactly one output only. It would be like saying "the conversion function from Celsius to Fahrenheit has 0 degrees C convert to both 32 degrees F and 50 degrees F at the same time". But such a statement makes no sense and it's not useful. So this is one example of why having one output makes sense for a function.

In short, we need one output for any given input. But the input x = 2 leads to more than one output. That's why we don't have a function.

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Point M is the midpoint of CD. What is the value of a in the figure?

liq [111]

Answer:

a=3

Step-by-step explanation:

Given points (a, b) and (c,d), the midpoint of the points will be at

((a+c)/2, ((b+d)/2)

Therefore, given (9, 2) and (a,2a), our midpoint is at

((9+a)/2, (2+2a)/2) = (6,4)

Matching the x values to their corresponding x values and doing the same with the y values, we get

(9+a)/2 = 6

(2+2a)/2 = 4

First, we have

(9+a)/2 = 6

multiply both sides by 2 to remove the denominator

9+a = 12

subtract 9 from both sides to isolate a

a = 3

2a = 2 * a = 6

Confirming this, we have

(2+2a)/2 = 4

(2+6)/2 = 4

8/2=4

8 0

2 years ago

Which statements describe the graph of y = 3√x-1+2 ? Check all that apply.

Reptile [31]

Answer:

The correct options are A, D and E.

Step-by-step explanation:

We are given the function $y=\sqrt[3]{x-1} +2$

From the graph below, we see that,

Domain and range of the function is the set of all real numbers.

As y-intercept is the point where the graph of the function crosses y-axis.

That is, y-intercept is obtained when x= 0.

So, on substituting, we have,

$y=\sqrt[3]{0-1} +2$

i.e. $y=-1+2$

i.e. y= 1

Thus, the y-intercept is (0,1).

Also, x-intercept is the point where the graph of the function crosses x-axis.

That is, x-intercept is obtained when y= 0.

So, on substituting, we have,

$0=\sqrt[3]{x-1} +2$

i.e. $-2=\sqrt[3]{x-1}$

i.e. $-8=x-1$

i.e. x= -7

Thus, the x-intercept is (-7,0).

Hence, the correct options for the function are,

A. The graph has a domain of all real numbers.

D. The graph has a y-intercept at (0, 1)

E. The graph has an x-intercept at (–7, 0).

3 0

2 years ago

Read 2 more answers

I need help please I don’t know what to it is due today

Kazeer [188]

Answer:

12 blue necklaces + 12 red necklaces = 24 necklaces. He will have 1 blue bead left over and 1 red bead left over.

Step-by-step explanation:

37/3 = 12.333 or 12 r1

25/2= 12.5 or 12 r1

1+1=2

6 0

2 years ago

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Brooke has scores of 84, 72, 90, 95, and 87 on her first five quizzes. After taking the sixth quiz, Brooke’s mean score increase

nexus9112 [7]

86, 90, and 92

Explanation:add all numbers together and divide it by the amount of numbers there are (5) and it comes out with 85.6 so it has to be higher since it increased

6 0

2 years ago

Helpp the topic is about limits

erik [133]

Since we want to find the value of k where the limit exists, set both equations equal to each other. Then substitute x = -1 in for each equation to find k.

$kx - 3 = {x}^{2} + k$