Answer:
-22/3 =x
Step-by-step explanation:
(4x-4) /(x+4) = 10
Multiply each side by (x+4)
(4x-4) /(x+4) * (x+4) = 10 * (x+4)
(4x-4) = 10 * (x+4)
Distribute
4x-4 = 10x+40
Subtract 4x from each side
4x-4-4x = 10-4x+40
-4 = 6x+40
subtract 40 from each side
-4 -40 = 6x+40-40
-44 = 6x
Divide each side by 6
-44/6 = -6x/6
-22/3 =x
When writing equivalent expressions, there are often several possible orders in which to simplify them. However, they will all take you to the same result as long as you do not make a mistake when using the properties. In this example, you will distribute the outer exponent first using the Power of a Product Property.
Answer:
18.66 ft/s
Step-by-step explanation:
The distance between you and the elevator is given by:

The rate of change for the distance between you and the elevator is given by:



Applying the chain rule:

Therefore, at x=300 and y = 500, dy/dt is:

The elevator is descending at 18.66 ft/s.
Answer:
10 ft
Step-by-step explanation:
Use theorem pythagoras
Length = x

the answer is 10 because length can't be in negative number
Answer:
Kinetic theory explains why the volume of a container must expand when the temperature of the gas inside increases in order for the pressure to remain constant.
Step-by-step explanation:
Charles' law: for a fixed mass of gas at constant pressure the volume is directly proportional to the temperature.
Analysis of a gas when its temperature increases according to kinetic theory:
The temperature has increased therefore the molecules have more kinetic energy, so they move with a greater velocity.¹
If the container's dimensions do not change the molecules will travel across the container between the walls in less time (because they are moving faster and covering the same distance between the container walls). This will increase the rate of collisions, which would increase the pressure.²
But if the dimensions of the container increased then the molecules would cover a larger distance faster thereby maintaining a constant rate of collisions. This would maintain a constant pressure.