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Anni [7]
2 years ago
8

I need help on this math problem.

Mathematics
1 answer:
olga nikolaevna [1]2 years ago
5 0
(not sure if this is right but)
x (to the 2nd power) + y (to the 2nd power) = cos (90) (to the 2nd power)
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Fine the missing exponent
alisha [4.7K]

Answer:

hi

Step-by-step explanation:

it is simple

4 =  {2}^{2}

have a nice day

8 0
2 years ago
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The diagram shows two nested triangles that share a vertex.Find a center and a scale factor for a dilation that would move the l
nasty-shy [4]

Transformation that changes the size of a shape is referred to as dilation.

  • The scale factor that moves the large triangle to the small one is 1/5
  • The center of dilation is: (-1,1)

<u>The center of dilation</u>

From the diagram (see attachment), the triangles share a common vertex at (-1,1)

This means that, the center of dilation is (-1,1)

<u>The scale factor of dilation</u>

To do this, we divide the side length of the small triangle with the corresponding side of the large triangle.

From the attached image:

\mathbf{Base\ of\ small\ triangle = 1}

\mathbf{Base\ of\ large\ triangle = 5}

So, the scale factor (k) from large to small is:

\mathbf{k = \frac{Base\ of\ small\ triangle}{Base\ of\ large\ triangle} }

\mathbf{k = \frac{1}{5} }

Read more about dilation at:

brainly.com/question/13176891

3 0
3 years ago
ILL GIVE U BRAINLIEST PLZZ HELP I DO FLVS
GrogVix [38]

Answer:

c the answer is c


Step-by-step explanation:


5 0
3 years ago
Find the area of the figure.<br> A. 50 ft^2<br> B. 41 ft^2<br> C. 42 ft^2<br> D. 38 ft^2
NikAS [45]

Answer:

I'm pretty sure its A

Step-by-step explanation:

3 0
2 years ago
We are standing on the top of a 320 foot tall building and launch a small object upward. The object's vertical altitude, measure
STALIN [3.7K]

Answer:

The highest altitude that the object reaches is 576 feet.

Step-by-step explanation:

The maximum altitude reached by the object can be found by using the first and second derivatives of the given function. (First and Second Derivative Tests). Let be h(t) = -16\cdot t^{2} + 128\cdot t + 320, the first and second derivatives are, respectively:

First Derivative

h'(t) = -32\cdot t +128

Second Derivative

h''(t) = -32

Then, the First and Second Derivative Test can be performed as follows. Let equalize the first derivative to zero and solve the resultant expression:

-32\cdot t +128 = 0

t = \frac{128}{32}\,s

t = 4\,s (Critical value)

The second derivative of the second-order polynomial presented above is a constant function and a negative number, which means that critical values leads to an absolute maximum, that is, the highest altitude reached by the object. Then, let is evaluate the function at the critical value:

h(4\,s) = -16\cdot (4\,s)^{2}+128\cdot (4\,s) +320

h(4\,s) = 576\,ft

The highest altitude that the object reaches is 576 feet.

6 0
3 years ago
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