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Delvig [45]
3 years ago
14

Please answer this question​

Mathematics
1 answer:
Free_Kalibri [48]3 years ago
5 0

Answer:

3

Step-by-step explanation:

log(3x^{3}) - log(x^{2}) = log(\frac{3x^{3}}{x^{2}})\\log(27) - log(x) = log(\frac{27}{x} )\\

therefore,

\frac{3x^{3} }{x^{2} } = \frac{27}{x} \\3x=\frac{27}{x} \\3x^{2} =27\\x= +3\\x=-3

however, since logarithms cannot have negative arguments, x can only be +3

i.e. log(-3) is impossible, and will return MATH ERROR on a calculator.

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Answer:

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Step-by-step explanation:

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Therefore;

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