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3 years ago

Please answer this question

Mathematics

1 answer:

Free_Kalibri [48]3 years ago

5 0

Answer:

Step-by-step explanation:

$log(3x^{3}) - log(x^{2}) = log(\frac{3x^{3}}{x^{2}})\\log(27) - log(x) = log(\frac{27}{x} )\\$

therefore,

$\frac{3x^{3} }{x^{2} } = \frac{27}{x} \\3x=\frac{27}{x} \\3x^{2} =27\\x= +3\\x=-3$

however, since logarithms cannot have negative arguments, x can only be +3

i.e. log(-3) is impossible, and will return MATH ERROR on a calculator.

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What’s the answer for a, and b, and how would you solve it?

xxTIMURxx [149]

Answer:

a) negative

b) -7/6

Step-by-step explanation:

The x value increased, but the y value decreased so the line goes down and has a negative slope

(y₁-y₂)/(x₁-x₂) is the slope where (x₁,y₁) and (x₂,y₂) are points on the line

(4-(-3))/(-1-5)=7/-6

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2 years ago

V-16=-32 I need help with the math worksheet how to solve the question

sergeinik [125]

You solve an equation like this by adding the opposite of the constant to both sides of the equation.

... V -16 +16 = -32 +16 . . . . . addition property of equality: if a=c, then a+b = c+b

... V + 0 = -16 . . . . . . . . . . . . additive inverse property of integers: -16+16 = 0

... V = -16 . . . . . . . . . . . . . . . identity element of addition: V+0 = V

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You can always do the same thing to both sides of an equation. Here, it is useful to add the opposite of -16 to both sides. That way the constant on the left becomes zero, so you only have the variable by itself—which is what you want.

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3 years ago

What is the slope of the line that passes through the pair of points?

Mazyrski [523]

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4 years ago

Read 2 more answers

Set up an equation and solve the following problem.

nordsb [41]

Answer:

The speed of Dave is 42 miles per hour

The speed of Kent is 46 miles per hour .

Step-by-step explanation:

Given as :

The distance cover by Dave = d = 210 miles

The time taken by Dave = t hour

The speed of Dave = s miph

Again

The distance cover by Kent = D = 230 miles

The time taken by Kent = T hour

The speed of Kent = S = (s + 4 ) miph

For Dave

Time = $\dfrac{\textrm Distance}{\textrm Speed}$

So, t = $\dfrac{\textrm d miles}{\textrm s miph}$

Or, t = $\dfrac{\textrm 210 miles}{\textrm s miph}$

For Kent

Time = $\dfrac{\textrm Distance}{\textrm Speed}$

So, T = $\dfrac{\textrm D miles}{\textrm S miph}$

Or, T = $\dfrac{\textrm 230 miles}{\textrm (s + 4) miph}$

∵ Time taken by both is same

So, t = T

Or, $\dfrac{\textrm 210 miles}{\textrm s miph}$ = $\dfrac{\textrm 230 miles}{\textrm (s + 4) miph}$

Or, 210 × (s + 4) = 230 × s

Or, 210 × s + 210 × 4 = 230 × s

Or, 210 × 4 = 230 × s -210 × s

Or, 210 × 4 = 20 × s

∴ s = $\dfrac{840}{20}$

i.e s = 42 miph

So, The speed of Dave = s = 42 miles per hour

Again

The speed of Kent = S = (s + 4 ) miph

i.e S = 42 + 4

or, S = 46 miph

So, The speed of Kent = S = 46 miles per hour

Hence,The speed of Dave is 42 miles per hour

And The speed of Kent is 46 miles per hour . Answer

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3 years ago

27. Stuart wants to play a trick on his friend by hiding his pencil in the box of tissues shown below. If

Alex17521 [72]

Answer:

Well if it’s a regular box I’m sure it will fit, because a box of tissues is at least 10 inches long in diameter.

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4 years ago

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