Answer:
We have, from distance formula.
AB² = (5-0)² + (2-6)² = 5² + 4² = 25 + 16 = 41
BC² = (0+5)² + (6+7)² = 5² + 13² = 25 + 169 =194
AC² = (5+5)² + (2+7)² = 10² + 9² = 100+81 = 181
Here, BC² ≠ AB² + AC².
So, the triangle is not a right triangle
I'm assuming that the signs inside each circle is its sign. So, negative sign in the circle means it is a negative number and vice versa.
a.) Given:
7 circles w/ negative signs, 4 out of 7 circles are crossed out.
- 7 - 4 = -11
b) Given:
7 circles with positive sings and 5 circles with negative signs. The 5 negative circles are crossed out.
+ 7 - (-5) = 7 + 5 = 12
I'm not sure if I am correct but I answered based on what I understand from the given data.
The perimeter = 2 * (3*y - 5) + 2*2*y = 6*y - 10 + 4*y = 10y - 10