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GalinKa [24]
3 years ago
14

Is the triangle with the vertices A(5,2), B(0,6), and C(-5, - 7) a right triangle?

Mathematics
2 answers:
gogolik [260]3 years ago
6 0

Answer:

We have, from distance formula.

AB² = (5-0)² + (2-6)² = 5² + 4² = 25 + 16 = 41

BC² = (0+5)² + (6+7)² = 5² + 13² = 25 + 169 =194

AC² = (5+5)² + (2+7)² = 10² + 9² = 100+81 = 181

Here, BC² ≠ AB² + AC².

So, the triangle is not a right triangle      

jek_recluse [69]3 years ago
6 0
No is the correct answer
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Expand and simplify<br>2(2y + 1) + 2(5y - 3)​
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Find the slope (3,6)<br> (3,-3) need in 5 minutes
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Answer: The slope is undefined.

Step-by-step explanation:

Using the formula given, find the difference in the y coordinates of the points and divide it by the x coordinates.

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x coordinates:   3- 3 = 0  

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4 0
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Graph y &gt; -1/3x+5<br><img src="https://tex.z-dn.net/?f=y%20%3E%20%20-%20%20%5Cfrac%7B1%7D%7B%203%20%7D%20x%20%2B%205" id="Tex
ad-work [718]

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The function is y>-\frac{1}{3} x+5

To graph the function, let us find the x and y intercepts.

To find x-intercept, let us substitute y=0 in the function y>-\frac{1}{3} x+5

\begin{aligned}0 &=-\frac{1}{3} x+5 \\-5 &=-\frac{1}{3} x \\x &=15\end{aligned}

Thus, the x-intercept is (15,0)

To find the y-intercept, let us substitute x=0, we get,

\begin{aligned}&y=-\frac{1}{3}(0)+5\\&y=5\end{aligned}

Thus, the y-intercept is (0,5)

The graph has no asymptotes.

To plot the points in the graph, we need to substitute the values for x in the function y>-\frac{1}{3} x+5, to find the y-values.

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