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3 years ago

(4m-n-3). 12n13 8m 20

Mathematics

1 answer:

JulsSmile [24]3 years ago

5 0

Answer:

24n^7/m^16

Step-by-step explanation:

Just simplify and rewrite what ever you get simplify again 2 times and now make the calculation as you see every big number is a whole number and is a pair.

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Answer this question please I need help

faust18 [17]

14872 is the answer.

4 0

3 years ago

Pete played in two basketball games. He scored 4 fewer points in the second game than he scored in the first. He scored 12 point

kiruha [24]

Answer:

Step-by-step explanation:

12+4=16

12 being the number he scored in the second game, and four being the ones he added to said score in the first game.

8 0

3 years ago

Read 2 more answers

[20points][Precal] Find the cross product of -(3/4)V and (1/2)w if v = <-2, 12, -3> and w = <-7, 4, -6>

Lana71 [14]

$\mathbf v=\langle-2,12,-3\rangle=-2\,\vec i+12\,\vec j-3\,\vec k$
$-\dfrac34\mathbf v=\dfrac32\,\vec i-9\,\vec j+\dfrac94\,\vec k$

$\mathbf w=\langle-7,4,-6\rangle=-7\,\vec i+4\,\vec j-6\,\vec k$
$\dfrac12\mathbf w=-\dfrac72\,\vec i+2\,\vec j-3\,\vec k$

$-\dfrac34\mathbf v\times\dfrac12\mathbf w=\begin{vmatrix}\vec i&\vec j&\vec k\\\frac32&-9&\frac94\\-\frac72&2&-3\end{vmatrix}$
$=\left((-9)\times(-3)-\dfrac94\times2\right)\,\vec i-\left(\dfrac32\times(-3)-\dfrac94\times\left(-\dfrac72\right)\right)\,\vec j+\left(\dfrac32\times2-(-9)\times\left(-\dfrac72\right)\right)\,\vec k$
$=\dfrac{45}2\,\vec i-\dfrac{27}8\,\vec j-\dfrac{57}2\,\vec k=\left\langle\dfrac{45}2,-\dfrac{27}8,-\dfrac{57}2\right\rangle$

6 0

3 years ago

A guy wire to a tower makes a 72 degrees angle with level ground. At a point 30 ft farther from the tower than the wire but on t

Andreyy89

So.. checking the picture below

we can say y = y, or just do a substitution and end up with

$\bf tan(72^o)=tan(30^o)(30+x)\implies 3.08x=\cfrac{30}{\sqrt{3}}+\cfrac{1}{\sqrt{3}}x
\\\\\\
3.08x-\cfrac{1}{\sqrt{3}}x=\cfrac{30}{\sqrt{3}}\implies 2.5x\approx 17.32\implies x\approx \cfrac{17.32}{2.5}$

once you know, how long is "x", then you can simply use the cosine of 72° to get "r"

thus $\bf cos(\theta)=\cfrac{adjacent}{hypotenuse}\qquad cos(72^o)=\cfrac{x}{r}\implies r=\cfrac{x}{cos(72^o)}$

6 0

3 years ago

Read 2 more answers

2x - 4<br> ——— =4<br> 5<br> Pls solve

Svetlanka [38]

Step-by-step explanation:

cross multiply

2x - 4 = 4 × 5

2x - 4 =20

collect like terms (CLT)

2x = 20 + 4

2x=24

divide both sides by 2

x=12

7 0

3 years ago