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soldier1979 [14.2K]
3 years ago
9

A person who is 6ft tall walks away from a streetlight. When the person is 15 feet away from the light, the tip of his shadow is

5 feet in front of him. Find the height of the streetlight
Mathematics
1 answer:
Citrus2011 [14]3 years ago
5 0
We essentially have a ratio here:
\frac{shadow}{actual}

Since we know the ratio is going to stay constant at \frac{5}{6}, we can use this to find the height of the lamp along with the information that the total distance from the lamp to the tip of his shadow is 20:
\frac{5}{6}=\frac{20}{h}
5h=120
h=24
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Answer:

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Step-by-step explanation:

Given:

J(-4, 11)

K(8, -1)

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Required:

Coordinates of P

SOLUTION:

Use the formula, (x, y) = (x_1 + k(x_2 - x_1), y_1 + k(y_2 - y_1)) to find the coordinates of point P, that partition the segment JK into the ratio 1/3.

Let,

J(-4, 11) = (x_1, y_1)

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k = \frac{1}{3}

Thus, plug in the values as follows:

P(x, y) = (-4 + \frac{1}{3}(8 -(-4)), 11 + \frac{1}{3}(-1 - 11)

P(x, y) = (-4 + \frac{1}{3}(12), 11 + \frac{1}{3}(-12)

P(x, y) = (-4 + \frac{12}{3}, 11 + \frac{-12}{3})

P(x, y) = (-4 + 4,  11 + (-4)

P(x, y) = (0, 7)

The coordinates of point P, are (0, 7)

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