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soldier1979 [14.2K]
3 years ago
9

A person who is 6ft tall walks away from a streetlight. When the person is 15 feet away from the light, the tip of his shadow is

5 feet in front of him. Find the height of the streetlight
Mathematics
1 answer:
Citrus2011 [14]3 years ago
5 0
We essentially have a ratio here:
\frac{shadow}{actual}

Since we know the ratio is going to stay constant at \frac{5}{6}, we can use this to find the height of the lamp along with the information that the total distance from the lamp to the tip of his shadow is 20:
\frac{5}{6}=\frac{20}{h}
5h=120
h=24
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Answer:

a) The perimeter of the rectangle =

= 22 units

b) The area of the rectangle

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Step-by-step explanation:

We solve the above question using the formula

= √(x2 - x1)² + (y2 - y1)²

When we are given vertices (x1, y1) and (x2, y2)

The vertices: (-1, -2), (-6, -2), (-6, -8), (-1, -8)

We have to find the length of the sides

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(-1, -2), (-6, -2)

= √(-6 - (-1))² +( -2 -(-2))²

= √-5² + 0²

= √25

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Side B

(-6, -2), (-6, -8)

= √(-6 - (-6))² + (-8 - (-2))²

= √(-6 +6)² + (-8 +2)²

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Side C

(-6, -8), (-1, -8)

= √(-1 - (-6))² +(-8 - (-8))²

= √(-1 + 6)² + (-8 + 8)²

=√ 5² + 0²

= √25

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Side D

(-1, -2), (-1, -8)

= √(-1 -(-1))² + (-8 - (-2))²

= √(-1 + 1)² + ( -8 + 2)²

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= √0 + 36

= √36

= 6 units

From the above calculation,

Side A = Side C = 5 units

Side B = Side D = 6 units

Hence, this polygon is a quadrilateral called the RECTANGLE.

Therefore:

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2L + 2W

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DIA [1.3K]

Answer:

T I hope this helps:D

6 0
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Answer:

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