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nydimaria [60]
2 years ago
13

Can someone please help me? It's 1:16am and its due at 7:15am. I've got school.

Mathematics
2 answers:
astra-53 [7]2 years ago
6 0

Answer:

2 v 13, 2 Square root 13

Step-by-step explanation:

there's 2 right triangles

a)

10^2 = 6^ + a^2

100 - 36 = a^2

64 = a ^2

a = 8

--------------------------------------------

now we know the base of the right triangle = 8

and also the base of the left one = 4

8 + 4 = 12

--------------------------------------------

now find x

b)

x^2 = 6^2 + 4^2

x^2 = 36 + 16

x^2 = 52

x = (square root) 52

x = 2 v 13     <---- "v = square root"

zavuch27 [327]2 years ago
3 0
<h2>Question :- Find the unknown side . </h2>

Instructions :- Simplify the answer if there is square root

<h2>Given :- </h2>
  1. Two triangles
  2. Total length of the base 12
  3. First triangle dimensions
  • 10 as it's hypotenuse
  • 6 as it's perpendicular

<h2>Answer:- X = ✓ 52 = 7.2</h2>

<h2>Explanation:- </h2>

<h3>Formula :- </h3>

hypotenuse² = perpendicular²+base²

<h3>Solution:- </h3>

First triangle:-

{h}^{2}  =  {p}^{2}  +  {b}^{2}  \\  {10}^{2}  =  {6}^{2}  +  {b}^{2}  \\ 100 = 36 +  {b}^{2}  \\ 100 - 36 =  {b}^{2}  \\ 64 =  {b}^{2}  \\ 8 =  b

Second triangle

  1. perpendicular = 6
  2. hypotenuse = X ( to Find )
  3. base = 12-b = 12-8= 4

{h}^{2}  =  {p}^{2}  +  {b}^{2}  \\  {x}^{2}   =   {6}^{2}  +  {4}^{2} \\  {x}^{2}  = 36 + 16 \\  {x}^{2}  = 52 \\ x =  \sqrt{52}  = 7.2 \\ x = 7 \:  \: approx

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