The decimal approximation for the trigonometric function sin 28°48' is
Given the trigonometric function is sin 28°48'
The ratio between the adjacent side and the hypotenuse is called cos(θ), whereas the ratio between the opposite side and the hypotenuse is called sin(θ). The sin(θ) and cos(θ) values for a given triangle are constant regardless of the triangle's size.
To solve this, we are going to convert 28°48' into degrees first, using the conversion factor 1' = 1/60°
sin (28°48') = sin(28° ₊ (48 × 1/60)°)
= sin(28° ₊ (48 /60)°)
= sin(28° ₊ 4°/5)
= sin(28° ₊ 0.8°)
= sin(28.8°)
= 0.481753
Therefore sin (28°48') is 0.481753.
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Answer:
No
Step-by-step explanation:
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Answers:
- Pizza Uno = $5.25
- Pizza Duo = $5.60
Those are the costs for a whole small pizza.
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Explanation:
Let
- x = cost of whole small pizza from Pizza Uno
- y = cost of whole small pizza from Pizza Duo
x and y are some dollar amount, so they cannot be negative numbers. It also doesn't make sense to have them be 0 either. So we'll make them positive.
2/3 of x is equal to 3.50 as the first sentence mentions. This forms the equation (2/3)*x = 3.50
Multiply both sides by the reciprocal of 2/3 to isolate x
(2/3)*x = 3.50
(3/2)*(2/3)*x = (3/2)*3.50
x = 5.25
Pizza Uno charges $5.25 for a whole small pizza.
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Pizza Duo charges $4.20 for 3/4 of a small pizza, meaning the equation we need to solve is
(3/4)y = 4.20
We'll use the same idea as the last equation to get...
(3/4)y = 4.20
(4/3)*(3/4)y = (4/3)*4.20
y = 5.60
Pizza Duo charges $5.60 for a whole small pizza.
Pizza Uno is the better deal (assuming both pizzas taste the same or you don't have a preference for either). You would save $5.60 - $5.25 = $0.35 = 35 cents.
The number of ways is 364 if the number of ways in which 4 squares can be chosen at random.
<h3>What are permutation and combination?</h3>
A permutation is the number of different ways a set can be organized; order matters in permutations, but not in combinations.
It is given that:
On a chessboard, four squares are randomly selected so that they are adjacent to each other and form a diagonal:
The required number of ways:
= 2(2[C(4, 4) + C(5, 4) + C(6, 4) + C(7, 4)] + C(8, 4))
= 2[2[ 1 + 5 + 15+35] + 70]
= 364
Thus, the number of ways is 364 if the number of ways in which 4 squares can be chosen at random.
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