All categories

2 years ago

Find the root(s) of f (x) = (x + 5)3(x - 9)2(x + 1). -5 with multiplicity 3 5 with multiplicity 3 -9

Mathematics

1 answer:

faust18 [17]2 years ago

4 0

Answer:

-5, multiplicity 3; +9, multiplicity 2; -1

Step-by-step explanation:

The roots of f(x) are those values of x that make the factors be zero. For a factor of x-a, the root is x=a, because a-a=0. If the factor appears n times, then the root has multiplicity n.

f(x) = (x+5)^3(x-9)^2(x+1) has roots ...

-5 with multiplicity 3
+9 with multiplicity 2
-1

You might be interested in

Is it rational or irrational

Nimfa-mama [501]

Math is real hard but I think irrational don’t quote me on that

7 0

3 years ago

Read 2 more answers

Need help with these math questions

PSYCHO15rus [73]

$\sqrt{16-x}$ x = 8

Since x = 8, you can plug in/substitute 8 for "x" in the equation:

$\sqrt{16-x}$

$\sqrt{16-8}$

$\sqrt{8}$

2.82842

2.83 You answer is the 4th option

$\sqrt{x+7}$ x = 9

Plug in 9 for "x" in the equation

$\sqrt{x+7}$

$\sqrt{9+7}$

$\sqrt{16}$

4 Your answer is the 1st option

4 0

2 years ago

The graph below shows the prices of different numbers of boots at a store: A graph is shown. The values on the x axis are 0, 2,

kobusy [5.1K]

Answer:

b=12.50p

Step-by-step explanation:

Given :

x y

0 0

2 25

4 50

6 75

8 100

10 125

To Find: Which equation can be used to determine p, the cost of b boots?

Solution :

Using point slope form Find the equation of line of the given coordinates

Let $(x_{1} , y_{1})=(0,0)$

Let $(x_{2} , y_{2})=(2,25)$

So, formula : $y-y_{1} =\frac{y_{2}- y_{1}}{x_{2}- x_{1}} *(x-x_{1})$

$y-0 =\frac{25-0}{2-0} *(x-0)$

$y= 12.50x$

Now we are given that cost of b boots is p

Since we are given that x axis is Number of Boots and y in price

So in the equation put x = b and y = p

So, equation : b=12.50p

Hence Option 4 is correct

5 0

3 years ago

Read 2 more answers

What is 31 billion in scientific notation?

zepelin [54]

Answer:

(3.10 x 10^10)

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

2. The robot was initially placed at position (6,9), and at = 2 seconds, its position is (10,15).

qaws [65]

$\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&&(~ 6 &,& 9~) 
% (c,d)
&&(~ 10 &,& 15~)
\end{array}~~~ 
% distance value
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
d=\sqrt{(10-6)^2+(15-9)^2}\implies d=\sqrt{4^2+6^2}\implies d=\sqrt{52}
\\\\\\
d\approx 7.2$

what's its speed? well, it traveled √(52) in 2 seconds, so is simply √(52)/2, which is about 3.6 units per second.

4 0

3 years ago