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Serjik [45]
2 years ago
5

Please solve these questions it's important please​

Mathematics
1 answer:
MissTica2 years ago
4 0

<h3>b)</h3>

\frac{3 {a}^{2}  - 9a}{ {a}^{2}  - 9}  =  \frac{3a(a - 3)}{(a + 3)(a - 3)}  =  \frac{3a}{a + 3}

<h3>c)</h3>

\frac{ {y}^{2} - 3yz -4  {z}^{2}  }{3 {y}^{2} - 12yz }  =  \frac{(y + z)(y - 4z)}{3y(y - 4z)}  =  \frac{y + z}{3y}

<h3>d)</h3>

\frac{ {d}^{2} + 4d  + 4}{ {d}^{2}  + 2d}  =  \frac{(d + 2)(d + 2)}{d(d + 2)}  =  \frac{d + 2}{d}

<h3>e)</h3>

\frac{5f - 15}{3 {f}^{2}  - 13f + 12}  =  \frac{5(f - 3)}{(3f - 4)(f - 3)}  =  \frac{5}{3f - 4}

I hope I helped you^_^

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The right answer is 3,107.21

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In the diagram below, quadrilateral ABCD has vertices A(-5,1), B(6,-1),C(3,5), and D(-2,7). What are the coordinates of the midp
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3 years ago
On a certain hot​ summer's day, 643 people used the public swimming pool. The daily prices are $1.50 for children and $2.00 for
lilavasa [31]

249 children and 394 adults swam at the public pool.

Step-by-step explanation:

Number of people swam at pool = 643

Receipts = $1161.50

Cost for one child = $1.50

Cost for one adult = $2.00

Let,

x be the number of children

y be the number of adults

According to given statement;

x+y=643    Eqn 1

1.50x+2.00y = 1161.50   Eqn 2

Multiplying Eqn 1 by 2

2(x+y=643)\\2x+2y=1286\ \ \ Eqn\ 3\\

Subtracting Eqn 2 from Eqn 3

(2x+2y)-(1.50x+2.00y)=1286-1161.50\\2x+2y-1.50x-2.00y=124.50\\0.5x=124.50

Dividing both sides by 0.5

\frac{0.5x}{0.5}=\frac{124.50}{0.5}\\x=249

Putting x=249 in Eqn 1

249+y=643\\y=643-249\\y=394

249 children and 394 adults swam at the public pool.

Keywords: linear equation, subtraction

Learn more about linear equations at:

  • brainly.com/question/5798698
  • brainly.com/question/5758530

#LearnwithBrainly

4 0
3 years ago
PLEASEE HELP.!! ILL GIVE BRAINLIEST.!! *EXTRA POINTS* DONT SKIP:((
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abcdefghijklmnopqrstuvwxyz

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3 years ago
Bro can someone help pleaseeee
Masteriza [31]
Same I need help, I will try to help u
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